Pb2+ + 2NaCl ----. PbCl2 + 2Na+
mole of PbCl2 = mass / molar mass
= 13.1 / 278
= 0.047 mol
mole ratio of NaCl to PbCl2 is 2 : 1
mole of NaCl = 0.5 * 0.047 = 0.094 mol
lestion 22 of 23 > How many moles of NaCl, if mixed with excess Pb2+ ions...
How many moles of NaCl, if mixed with excess Pb2+ ions in solution, would be needed to form 11.7 g of PbCl2?
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please solve and show work and give the moles needed for NaCl and grams needed for NaCl the volume of the flask is 250ml Experiment 11 Solutions and Molarity DATA &CALCULATIONS 1) Determine the mass of NaCI(s) needed to make a 1.38M solution in your flask setup: mol NaCl needed lasts = mol NaCI needed 1.38M x yolum 1000 g NaCl needed mol NaCI needed X MMNG NaCI needed 2) Calculate the volume of 4.00M solution you need to pipette...
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86.796 Resources Check Answer Question 21 of 45 > Using the balanced chemical equation, determine how many moles of NaCl will be produced, if 0.238 mol of BaCl, is allowed to react with an excess of Na, so moles of NaCI: mol Using the moles of NaCl found in the previous question, determine how many grams of NaCl can be produced. mass of NaCI: Using the moles of NaCl found in a previous question, determine how many formula units of...
Need help please. 22. I believe a. is 2 moles and b. is 2 moles 23. 2 moles of Ben gives 1 mole of product= which should equal 121.65 grams. But need help not sure if they are correct and I don't know 24. 22. For the following Aldol Condensation: To make one mole of product, how many moles of each reactant are needed? 0. NaOH CH CHCCH CH FW-106.13 d-1.0415 grnL F-58.08 g/mol d-0.7899 gmL Mp 110.5-112 °C FW...