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lestion 22 of 23 > How many moles of NaCl, if mixed with excess Pb2+ ions in solution, would be needed to form 13.1 g of PbCI
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Answer #1

Pb2+ + 2NaCl ----. PbCl2 + 2Na+

mole of PbCl2 = mass / molar mass

= 13.1 / 278

= 0.047 mol

mole ratio of NaCl to PbCl2 is 2 : 1

mole of NaCl = 0.5 * 0.047 = 0.094 mol

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