Question

Summarize the given assembly language program:

.text .globl main la $50, size lw $sl, 0 ($80) ori $s2, $o, O ori $s3, $0, O ori $sd, $0, O # initialize registers # $sl = size # $92 sum # $s3 = pos # $54 = neg # <init> ori $55, $o, O la $56, arr # $55 = i # $86 Sarr Li: # if (ceond>) bge $55, $81, DONE <for-body> lw $57, 0($56) addu $s2, $s2, $s7 blez $37, NEG addu $s3, $s3, $s7 # $S7 = arr[i] #sum + arr[i] #it ! (arr[i] > 0) # pos += arr[i]; NEG: UPDATE bgez $87, UPDATE addu $54, $54, $s7 #goto UPDATE # it ! (arr[i] < 0) # neg += arr[i]: UPDATE: # Cupdate> addi Ss5, $55, 1 # i++ addi $86, $86, 4 # move array pointer L1 # qoto L1 DONE: # initialize data .data size: .word 10 arr: .word 12, -1, 8, O, 6, 85, -74, 23, 99, -30

Answer 1

The Program takes in the 10 integers (either positive or negative).

It would sum up all the positive integers and save it to POS.

and sum up all the negative integers and save it to NEG.

It wouldn't print any result to the console.