Question

A manufacturer of automobile shock absorbers was interested in comparing the durability of its shocks with that of the shocks produced by its biggest competitor. To make the comparison, one of the manufacturer's and one of the competitor's shock absorbers were randomly selected and installed on the rear wheels of each of six cars. After the cars had been driven for 20,000 miles, the strength of each test shock absorber was measured, coded, and recorded; results are shown in the table below. Shock Absorber Strength Manufacturer's Car Competitor's WN - Find the p-value of the Normality test necessary to validate the procedure that is routinely used to analyze such data. a. 0.417 b.0.275 c. 0.133 d.0.380 e. 0.421

Answer 1

putting difference data of above in normality test:

option B is correct: 0.275

Probability Plot of (a-b) Normal - 95% CI Mean stDev 0.4167 0.1329 ------ ----------- ----- -- - --- - -- -- ----- --- ----- AD -ה 0.380 P-Value 0.275 ד ד ----- דרך -ו- Percent -- הזדדדדדד ר-ד הד-ח-ז-ר-ד-ו- -- דר -- -- -ד- -- ---- -- 0.0 0.2 0.6 0.8 1.0 0.4 (a-b)