To what temperature in K must a variable volume container of helium gas be cooled to obtain a final volume of 0.456 L? The initial volume and temperature are 1.02 L and 344 K, respectively. The pressure and number of moles are fixed.
Given:
Ti = 344.0 K
Vi = 1.02 L
Vf = 0.456 L
use:
Vi/Ti = Vf/Tf
1.02 L / 344.0 K = 0.456 L / Tf
Tf = 154 K
Answer: 154 K
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