Question

2. If I contain 3 moles of gas in a container with a volume of 60 liters and at a temperature of 400 K, what is the pressure inside the container?

3. If I have 7.7 moles of gas at a pressure of 0.09 atm and at a temperature of 56 ⁰C, what is the volume of the container that the gas is in?

4. If 0.500 mol N₂(g) has a volume of 11.0 L at some temperature and pressure, what volume would 0.750 mol CO₂(g) have at the same temperature and pressure?

Answer 1

Given Volume of the gas V 60.000 Pressure of the gas P atm Temperature of gas T = Ideal gas constant R= 400.0 K L atm Mol-1 K-1 0.0821 Number of moles of Gas (n) mol 3.00 Ideal gas equation is PV =n RT so moles of Gas n= PV/ RT Substitite all the vaues in the above equation to get p value Pressure of the Gas P= nRT/V mol x 0.0821 Latm Mol-1 K-1 400 K x 60.0 3.00 L.64 atm so Pressure of gas P 1.64 atm Given Volume of the gas V = Pressure of the gas P Temperature of gas T ? L 0.09 atm "С 56.0 56.0 273 = 329.0 K Ideal gas constant R L atm Mol-1 K-1 0.0821 Number of moles of Gas (n) mol 7.70 Ideal gas equation is PV n RT so Volume of Gas V =nRT/ P Substitite all the vaues in the above equation to get V value nRT/V 0.0821 Latm Mol-1 K-1 Moles of Gas V= 7.70 mol x 0.09 329 Кх atm 2310.933 L so Volume of 2311 gas V