Given:
Q = 23.1 J
m = 11 g
C = 0.134 J/g.oC
Ti = 22 oC
use:
Q = m*C*(Tf-Ti)
23.1 = 11.0*0.134*(Tf-22.0)
Tf -22.0 = 15.7 oC
Tf = 37.7 oC
Answer: 37.7 oC
Uthe temper e d A sample of s t ate is heated with an electrical coil 1 23.1 Joules oferty we added to a 110 rum sa...
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