Question
20.21.24.25
are dice 16. Suppose you roll two fair dice. Give an example of two independent events. Given an example of two disjoint even
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20 . Expected value : In simple it is long term average of random variable X.

For example : If you are playing a die game

rules are like this : if die shows 4 you will get 150 bucks

if not 4 you will loss 10 bucks

So how much do you make in a long run whether you will make profit or gain this can be answered by expected value.if expected value is -ve then it is benefited to casino and if it is positive it is benefited to you(player).

Here what is the chance of getting 4 is 1/6

therefore not getting 4 is 5/6

Then EV = 1/6*150+ 5/6*-10 = 16.67 Since it is positive value in long run you will be benefited.

21 . Variance :

Consider the height of a human being, suppose it has a mean of 1.7 meters. But nobody you actually meet has an exact height of 1.7 meter. Every deviates a bit from this mean even though it is expected height of any one you see. What the variance (or better the still the standard deviation) measures is the probability that random person you meet will be this much away from the mean.

If the variance is tiny, then there is almost no way you will meet someone who is 1.9 and above or 1.5 and below. On the other hand, if the variance is huge, there high chance to meet someone who is 2.0 or 1.4.

24. P(Correct) = 1/2 ,P(Wrong) =1/2

Assumption : took equal probability for correct and wrong.

if question is correct you will get 1 mark if it is wrong you will lose 1/3 marks.

This exam has 25 questions.

Expected no of marks for guessing all 25 questions is : 25*(1/2*1-1/2*1/3) = 8.34

25 . Suppose there is an exam with 50 True/False and 50 multiple choice questions with 5 options.

P(C) = 1/2 and P(W) = 1/2 for true/false questions

P(c) = 1/5 and P(w) = 4/5 for MCQ's

Expected no of questions getting correct = 50*P(C) + 50 *P(c) =50*1/2 + 50*1/5 = 25 + 10 = 35 questions

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