Question

Nomenclature Coordinate Complexes | <Br< SCN < Cl< O=N-0 <F <OH <C:0-(oxalato) < 0,2-<H2O <SCN <NH; <en (H2NCH2CH2NH2) NO2 <CN <CO Formula Name # of lone de [Cr. (NH3)3 (+20)})( triamminetriaquachromium(III) chloride [Fe(NH3).](NO2) hexaammineiron (111) nitrate [pt leng (12232 dithicyanodi(ethylenediamine)platinum(IV) chloride [Co(C204)(CO)]* Owlbunyoleation contu) lon ammonium tetraiodicuprate(II) INHO), [LUIGI Ke[Fe(ONO).] [ Fel NH3)6] hexaammineiron(III) hexahydroxochromate(III) [Co(H2NCH2CH2NH3)4](SO4)3 | +r15 4+ hy • he ºlfa wine) ¢e bal} (1) v10a4e pentaaquahydroxoiron(III) ion [Fe(H2E), GH) +2. (NH4)[Ni(O2)2(H2O)2] ammunium cinquabiscova lato) nickelate CI) AN TORID

Answer 1

1) Formula is correct and d electrons in Cr3+ is 3.

2) Name : hexaammineiron(III) nitrite

D-electrons are 5.

3) Formula : [Pt(en)₂(SCN)₂]Cl_{​​​​​2}

D-electrons are 6

4) Name Correct. D-electrons are 6

5) Formula correct. D-ELECTRONS are 9

6) Name : potassium hexanitrito-O-ferrate(II)

D-ELECTRONS are 6

7) Formula : [Fe(NH3)₆][Cr(OH)₆]

D-ELECTRONS in Fe are 5

D-ELECTRONS in Cr are 3

8) Name Correct. D-ELECTRONS are 6

9)Formula correct. D-ELECTRONS are 5

10) Name : ammonium diaquabis-(dioxygen)nickelate(II)

D-ELECTRONS are 8