Question

Spring 2020 E. Carbohydrates Part 1: In the box, draw the Fischer projection (linear conformation) that corresponds to the Haworth projection sugar given below. Note: This sugar is a ketose. (6 pts) СН2 она to 2 но - н 3 н он ч CH,OH Р +он 5 ОН 5 Н НО а H снаби о Сн,он ОН Н Part 2: Draw the Haworth projection of the given monosaccharide as a 6-sided a-pyranose ring. (7 pts) Н. 0 / са он е но-с-н но 0 Он н-с-он 3 но-с-н 4 Н H Но 4 Н H нс - он 5 6H H 4 CH, OH be Part 3: Name the glycosidic bond that links the disaccharide given below, using the accepted shorthand demonstrated in class. (3 pts) CH,OH н н н он Н но Ans: 0 H ОН CH₂ H Н он Н но ОН H ОН 9

Answer 1

Part 1 4₂0H 애 5 4 oh 2 n CH₂ of H H 1 To covert this into fischer projection we need to breck the co bond and form the chain by keeping the G at uppermost. on the top so the on group on right side. Here the o us bonded between C₂ & C5 an Here ch, on group is crebon nill Fischer projection: - 2 C- CH₂OH HO3(-H 5th be Gyol Hycol sc. duzon Hs eu, on 071 -o on Part 2: 1-6=0 Ho²6-H H-36-oh no tu -se-on 애 и 4 On 1 H Hell the off in the fischer projection on is on the left hand side so it will be at the top in Haworth projection formula . H- 1 2 и 11 6 Part-3. Euzon O 4 - non-reducing ghose unit 4 1 e 3 Glycosidic linkage. и 4 А. 5 reducing gluase unit 1 4 M on 0 2 ܓ 3 и 64 This is called G-qa-Glycosidic linkage In this disaccharide the ca of first Glucose unit is linked to the ce of another gluose unit. G-4 d- Glycosidic lintage. Aus