Question

Assembly language x86 processors in c++

Suppose the content of ax register is OxAFBB. Write program to do the following 16 15 14 13 12 11 10 987 6 5 4 3 2 1 1 1 0 0 a. Count and display the number of ones b. Determine whether the bit number 8 is on or off c. The bits 14,13,12,11 indicates the number of doors open (1011 means 8+2+1-11 doors open). Determine how many doors are open 01 0

Answer 1

code:

#include<iostream>
#include<stdlib.h>
using namespace std;
int main()
{
string ax;
int d,n=0,i,r;
cout<<"enter the 4 digit hexadecimal value:";
cin>>ax;

//cout<<sizeof(ax);
bool a[17],b[17];
for(int k=0; k<sizeof(ax); k++)//this loop converts hexa decomal to binary
{
i=k;
if(isdigit(ax[k]))
{
//cout<<ax[k];
d=ax[k]-'0';
a[i*4+1]=d%2;
a[i*4+2]=(d/2)%2;
a[i*4+3]=((d/2)/2)%2;
a[i*4+4]=(((d/2)/2)/2)%2;
}
if(ax[k]=='A')
{
//cout<<ax[k];
a[i*4+1]=1;
a[i*4+2]=0;
a[i*4+3]=1;
a[i*4+4]=0;
//cout<<a[i*4]<<a[i*4-1];
}
if(ax[k]=='B')
{
//cout<<ax[k];
a[i*4+1]=1;
a[i*4+2]=0;
a[i*4+3]=1;
a[i*4+4]=1;
}
if(ax[k]=='C')
{
//cout<<ax[k];
a[i*4+1]=1;
a[i*4+2]=1;
a[i*4+3]=0;
a[i*4+4]=0;
}
if(ax[k]=='D')
{
//cout<<ax[k];
a[i*4+1]=1;
a[i*4+2]=1;
a[i*4+3]=0;
a[i*4+4]=1;
}
if(ax[k]=='E')
{
//cout<<ax[k];
a[i*4+1]=1;
a[i*4+2]=1;
a[i*4+3]=1;
a[i*4+4]=0;
}
if(ax[k]=='F')
{
//cout<<ax[k];
a[i*4+1]=1;
a[i*4+2]=1;
a[i*4+3]=1;
a[i*4+4]=1;
}
}
for(int j=1; j<=16; j++)//this loop calculates number of one's
{
cout<<a[j]<<' ';
if(a[j]==1)
{
n++;
}
}
for(int j=1;j<=16;j++)
{
b[j]=a[17-j];
}
cout<<"number of one's are:"<<n<<endl;
if(b[8]==1)
{
cout<<"it is ON"<<endl;
}
else{
cout<<"it is OFF"<<endl;
}
r=b[14]*8+b[13]*4+b[12]*2+b[11]*1;
// cout<<b[14]<<b[13]<<b[12]<<b[11];
cout<<"Number of doors open :"<<r;
return 0;
}

output:

$CODE-PRACTISE Unti CAUsersN.Vishnuvardhan\Desktopl Ctled5.exe enter the 4 digit hexadecimal value:AFBB it is ON Number of doors open :11 Process returned e (ex execution time 5.352 s Press any key to continue 10:53 AM 10/14/2018$