Question

3.6 kif P13.2 - 50 ft в с — 30 ft — 50 ft – Problem 13.2
EI is constant
analyze the beam using the moment distribution method and draw shear and moment diagram
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Answer #1

3.6 klft mm 4 50 ft be : 30ft bo nom 50 ft ome 12 Step@ fixed end moment. (FEM):- for Span AB; MFAB = -w = - 306x (50) = - 7Step (3) Moment distribution : Membek | Ag ga Вс. CB/CD DC DE FEM -750 750 -270 270 | -750 750 - 120 - 300 300 | Balance B3.6 klft 570 RB2 30 15 - 0 Emic=0 => Rexx (30) – 570 +570–3-6630) - RB2 = 54k (1) Efy=o > Rea = 3.6*30 - RB2 » Req = 54.k (1)

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