Question

Part 4. Molality of the calcium chloride solution Molality is defined as mol solute Calculate the molality of your assigned calcium chloride solution. Assume that the density of kg solvent water is 1g/mL. Questions (SHOW ALL WORK) 1. Calculate the molarity (M) of a solution when 12.80 g of glycerol (CHsOs) is added to 40.70 g of water. The density of the solution is 1,052g/ml Colligative properties like boiling point elevation depend on the number of solute particles in solution. 2. a) Give the equation for the ionization of 1 mol of calcium chloride in water. b) Calculate the molality (m) of ion particles for your assigned calcium chloride solution

Answer 1

Q1. mass of glycerol = 12.80 g

mass of water = 40.70 g

mass of solution = mass of glycerol + mass of water

mass of solution = 12.80 g + 40.70 g

mass of solution = 53.50 g

volume of solution = (mass of solution) / (density of solution)

volume of solution = 53.50 g / (1.052 g/mL)

volume of solution = 50.86 mL

volume of solution = 0.05086 L

moles of glycerol = (mass of glycerol) / (molar mass of glycerol)

moles of glycerol = (12.80 g) / (92.09 g/mol)

moles of glycerol = 0.1390 mol

molarity of glycerol = moles of glycerol / volume of solution (L)

molarity of glycerol = (0.1390 mol) / (0.05086 L)

molarity of glycerol = 2.733 M