in vertical direction,
a = g = 9.8 m/s^2
u = 0 and time = t
so second equation of motion
s = u t + 0.5 * a * t ^2
15.7 = 0 + 0.5 * 9.8 * t^2
t = 1.7899 s
in horizontal direction,
t = 1.7899 s and distance travelled = 26.5 m as there is no acceleration in horizontal direction
so V = 26.5 / 1.7899
V = 14.8 m/s
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