QUESTION 105 The two equilibrium constants for the same reaction, Kc and Kp. will always equal...
The equilibrium constant, Kc, is calculated using molar concentrations. For gaseous reactions another form of the equilibrium constant, Kp, is calculated from partial pressures instead of concentrations. These two equilibrium constants are related by the equation Kp=Kc(RT)?n where R=0.08206 L?atm/(K?mol), T is the absolute temperature, and ?n is the change in the number of moles of gas (sum moles products - sum moles reactants). For example, consider the reaction N2(g)+3H2(g)?2NH3(g) for which ?n=2?(1+3)=?2. Part A For the reaction 3A(g)+3B(g)?C(g) Kc...
The equilibrium constant, Kc, is calculated using molar concentrations. For gaseous reactions another form of the equilibrium constant, Kp, is calculated from partial pressures instead of concentrations. These two equilibrium constants are related by the equation Kp=Kc(RT)Δn where R=0.08206 L⋅atm/(K⋅mol), T is the absolute temperature, and Δn is the change in the number of moles of gas (sum moles products - sum moles reactants). For example, consider the reaction N2(g)+3H2(g)⇌2NH3(g) for which Δn=2−(1+3)=−2. A) For the reaction 3A(g)+3B(g)⇌C(g) Kc =...
The equilibrium constant, Kc, is calculated using molar concentrations. For gaseous reactions another form of the equilibrium constant, Kp, is calculated from partial pressures instead of concentrations. These two equilibrium constants are related by the equation Kp=Kc(RT)Δn where R=0.08206 L⋅atm/(K⋅mol), T is the absolute temperature, and Δn is the change in the number of moles of gas (sum moles products - sum moles reactants). For example, consider the reaction N2(g)+3H2(g)⇌2NH3(g) for which Δn=2−(1+3)=−2. For the reaction 2A(g)+2B(g)⇌C(g) Kc = 80.2...
Q(22) Kp=Kc when? A) The reaction is at equilibrium B) The reaction is exothermic C) The reaction is endothermic D) all of the gasses present are at the same temperature E) the number of moles of gas on both sides of the balanced equation is the same. Q(23) HAH +A at the equilibrium (HA) = 1.65* 10-2 M and [H") = (A-) = 5.44*10-4 M at equilibrium. Kc = A) 1.7 X 10-1 C) 1.7 X 103 D) 1.7 X...
1. The equilibrium constant, Kc, is calculated using molar concentrations. For gaseous reactions another form of the equilibrium constant, Kp, is calculated from partial pressures instead of concentrations. These two equilibrium constants are related by the equation Kp=Kc(RT)Δn where R=0.08206 L⋅atm/(K⋅mol), T is the absolute temperature, and Δn is the change in the number of moles of gas (sum moles products - sum moles reactants). For example, consider the reaction N2(g)+3H2(g)⇌2NH3(g) for which Δn=2−(1+3)=−2. Part A For the reaction 3A(g)+2B(g)⇌C(g)...
, The equilibrium constant, Kc, is calculated using molar concentrations. For gaseous reactions another form of the equilibrium constant, Kp, is calculated from partial pressures instead of concentrations. These two equilibrium constants are related by the equation Part A Kp = K.(RT)An For the reaction 3A(g) + 2B(g) = C(g) where R=0.08206 L.atm/(K·mol), T is the absolute temperature, and An is the change in the number of moles of gas (sum moles products - sum moles reactants). For example, consider...
Chapter 15 Homework Pressure-Based versus Concentration-Based Equilibrium Constants 11 of 41 Review I Constants I Periodic Table The equilibrium constant, K is calculated using molar concentrations. For gaseous reactions another form of the equilibrium constant, Kp, is calculated from partial pressures instead of concentrations. These two equilibrium constants are related by the equation Part A For the reaction 3A(g)3B(g)C(g) Kp = Kc(RT)^n Ke 68.8 ta temperature of 273 C where R 0.08206 L atm/(K.mol), T is the absolute temperature, and...
Part A For the reaction The equilibrium constant, Kc is calculated using molar concentrations. For gaseous reactions another form of the equilibrium constant, Kp. is calculated from partial pressures instead of concentrations. These two equilibrium constants are related by the equation K = K (RT)An where R=0.08206 L-atın/K mol). T is the absolute temperature, and An is the change in the number of moles of gas (sum moles products - sum moles reactants). For example, consider the reaction N (g)...
Chapter 15 - Equilibrium Pressure-Based versus Concentration-Based Equilibrium Constants 22 of 58 Review Constants Periodic Table Part A For the reaction 2A(g) + 3B(g) = C(g) The equilibrium constant, ko is calculated using molar concentrations. For gaseous reactions another form of the equilibrium constant, Kp, is calculated from parlial pressures instead of concentrations. These two equilibrium constants are related by the equation K = K (RT) where R=0.08206 Latin/(K. Inol), T is the absolute temperature, and An is the change...
1. Which statement about a balanced chemical reaction equation is always correct? The total number of moles of the products equals the total number of moles of the reactants. b. The sum of the masses of gaseous reactants equals the sum of the masses of gaseous products. The sum of the stoichiometric coefficients for the products equals the sum of the stoichiometric coefficients for the reactants. The number of atoms of the products is higher to the numbers of atoms...