Homework Answers
Here, for the combined acceleration
acceleration , a = net force/total mass
a = 90/(4 * 10)
a = 2.25 m/s^2
Now, for the block 3 and 4
Using Netwons second law
F23 = a * (m2 + m3)
F23 = 2.25 * 20 = 45 N
the total force exerted by block 2 on block 3 is 45 N
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> You have to add the vertical for into it as well, which is the normal force of 2 on 3 = (20*9.81). Then with the 45 already calculated, calculate the hypotenuse. so 45^2 + 196.2^2 = (F23)^2
Mike Coxlong Sat, Feb 5, 2022 2:02 PM