Question

Question 5 (Mandatory) (2 points) Light shines through two polarizers whose axes are at an angle of 60 degrees with respect to each other. What is the ratio of the light intensity that exits the second polarizer to the light that exits the first? Round your answer to 2 decimal places. Your Answer

Answer 1

Since the second polarizer is at an angle of $60^{\circ}$ with respect to the first one, we can use the law that the Intensity coming out of the second one is

$I_{2}=I_{1}cos^{2}(\theta) \implies \frac{I_{2}}{I_{1}} =cos^{2}(60^{\circ})= 0.25$

which is the asked ratio.