Question

03 Consider Figure (Q3). Find the current through the 1 0 resistor using Theyenin equivalent sircuit method 6Ω 6Ω 2 18 V 4Ω Rt 1Ω Figure (Q3) เว 30 +101, -0 loi3 lo

Answer 1

R_th: To calculate R_th open current source, short CKT voltage source and Remove load resistor therefore R_th = (6 + 6) Vertical-bar Vertical-bar _4 R_th = (12)(4)/12 + 4 = 3 ohm Apply nodal plusminus V. V - 18/6 - 3 + V/4 + 6 = 0 V - 8/6 + V/10 = 3 5(V - 8) + 3V/30 = 3 8V - 40 = 90 8V = 130 = > V = 16.25 Volts \r\n Current through 4 ohm I_4 ohm = V/4 + 6 = 16.25/10 = 1.625 ohm therefore V_th = (4)(I_4 ohm) V_th = (4)(1.625) = 6.5 Volts Equivalent CKT therefore Current thorough 1 ohm is I_1 ohm = V_th/R_th + 1 = 6.5/. + 1 I_1 ohm = 1.625 Amp