Question

A 49.6 kg man walks to the end of a 31.9 kg, 13.0 m long diving board, that is being supported at two points separated by a distance X = 3.91 m. How big of a force is needed on the far left side, so that the diver can make it to the end of the board? (this is the force of the 'push pin' in the image shown here)

   

Q#2. What is the force on the support closer to the center of the board, when the diver is at the end of the board?

   

Answer 1

O Here, we need to balance the net moment about support closer to center. so let the force required at the end downwards. support be f acting Now, 3.9 mg (F* 3.91) = mg ( 12 - 3.91) + mg ( 13 - 3.91) F - (31.9x9.8 x 2.59)+ (49.6 x 9.8 x9.09) 391 &= 1337.12 N the force needed on far left end = 1337.12 N (downward) ② Here, {fy = 0 R = + (m + M) = 1337.12 + (31.9+49.6x9.8. Reaction R=2135.82 N force on the support closer to center = 2135.82 N. Hence, the