Question

1) A diver stand on top of a 4.6 m long diving board. The diving board is supported by the two brackets as shown in the picture above. The diver has a mass of 50 kg (a) What is the value and direction of the force each bracket exerts on the diving board (b) If the diver backs away from the edge of the diving board, what will happen to these two forces? Justify your answer. (c) If the bars on the left bracket can only handle 2500 N of force before it snaps, what is the maximum mass a person can have and stand on the edge of the board?

Answer 1

a) Net force in vertical direction is zero F_1 + F_2 + Mg = 0 F_1 + F_2 = -Mg rightarrow (1) Net about A should be zero F_2 times 1.2 + mg times 4.6 = 0 rightarrow (2) F_2 = -1878.33 N [M = 50 kg g = 9.8 m/s^2] F_1 = 1388.33 N so F is downward direction F_2 is in upward direction b) if diver back�s a way form edge then x will decrease F_2 times 1.2 + mg times x = 0 F_2 will decrease then F_1 will increase c) F_1 = 2500 N about B should be zero F_1 times 1.2 = mg times 3.4 M = 2500 times 1.2/9.8 times 3.4 = 90 kg