A stock's current price is $72. A call option with 3-month maturity and strike price of $ 68 is trading for 6, while a put with the same strike and expiration is trading for $20. The risk free rate is 2%. How much arbitrage profit can you make by selling the put and purchasing a synthetic put? (Provide your answer rounded to two decimals.)
You have purchased a put option for $ 11 three months ago. The option's strike price is $ 340. How much is your profit, if the stock price at expiration is $ 364?
A call option with X=$63 expires in half a year. The underlying stock's current price is $70 and its standard deviation is 40%. What is the Black-Scholes price of the call if the risk free rate is 2%? (Enter your answer rounded to two digits.)
Part A. As per the put call parity, we have C + PV(Strike Price) = P + S0 ; where C is the price of call, P is the price of put and S0 is current stock price.
PV (strike Price ) = 68 * e-rt = 68 * e-2%*3/12 = 67.66
Hence we have LHS if equation = 6+ 67.66 = 73.66
RHS of equation = 72 + 20 = 92. Hence there is arbitrage as below:
Part B : Since the expiry price is above the put strike price, there will be loss equal to the premium paid which is $11
Part C : B.S formula for call option:
C = N(d1) S0 - Xe-rtN(d2)
d1 = [(ln(S0/X) + t*(r + ((annualised volatility)2)/2)]/(annual volatility * (t)1/2)
d2 = d1 - (annual volatility * (t)1/2)
Plugging in the values and solving we get :
S0 = 70 ; X = 63 ; annualised vol = 40% ; r = 2% t = 0.5 years
d1 = 0.3753 & d2 = 0.0925
N(d1) = 0.6443 (used normal distribution table which is for 2 digits only)
N(d2) = 0.5359
C = 0.6443 * 70 - 63*e-2%*0.5*0.5359 = 11.68 which is the price of call option.
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