Question

Question 5 2 pts Country Financial, a financial services company, uses surveys of adults age 18 and older to determine if personal financial fitness is changing over time (USA Today, April 4, 2012). In February of 2012, a sample of 1000 adults showed 410 indicating that their financial security was more than fair. In February of 2010, a sample of 900 adults showed 315 indicating that their financial security was more than fair What is a 95% confidence interval estimate of the difference between the proportions at the two years, 2012 and 2010? (LCL, UCL) = (2.08, 5.84) (LCL, UCL) = (0.81, 7.11) (LCL, UCL) = (2.38,5.54) (LCL, UCL) = (1.49,6.43) Question 6 2 pts Country Financial, a financial services company, uses surveys of adults age 18 and older to determine if personal financial fitness is changing over time (USA Today, April 4, 2012). In February of 2012, a sample of 1000 adults showed 410 indicating that their financial security was more than fair. In February of 2010, a sample of 900 adults showed 315 indicating that their financial security was more than fair. What is the point estimate of the difference between the proportions at the two years, 2012 and 2010 ? Round to 2 decimal places. Question 7 2 pts Country Financial, a financial services company, uses surveys of adults age 18 and older to determine if personal financial fitness is changing over time (USA Today, April 4, 2012). In February of 2012, a sample of 1000 adults showed 410 indicating that their financial security was more than fair. In February of 2010, a sample of 900 adults showed 315 indicating that their financial security was more than fair. What is a 99% confidence interval estimate of the difference between the proportions at the two years, 2012 and 2010? (LCL, UCL) = (1.49,6.43) (LCL, UCL) = (0.81, 7.11) (LCL, UCL) = (2.08, 5.84) (LCL, UCL) = (2.38,5.54) Question 8 2 pts Country Financial, a financial services company, uses surveys of adults age 18 and older to determine if personal financial fitness is changing over time (USA Today, April 4, 2012). In February of 2012, a sample of 1000 adults showed 410 indicating that their financial security was more than fair. In February of 2010, a sample of 900 adults showed 315 indicating that their financial security was more than fair. At 99% confidence, what is the margin of error? Round to 2 decimal places.

Answer 1

CI Intervals = (0.0164,0.1036) 5 & 6) Given = x1 = 410 ni = 1000 Now, Margin of error (E) = x2 = 315 n2 = 900 Point estimate = 0.06 = Standard error * Za|2 p1 = x1/n1 = 410 / 1000 = 0.4100 p2 = x2/n2 = 315 / 900 = 0.3500 = 0.0222*1.96 = 0.0436 Therefore a) lower limit = 1.960 At 95% CI level = 2212 - Here, pl-p2 = = 0.41-0.35 0.0600 = (p1-p2)-E = 0.06 -0.0436 = 0.0164 b) upper limit= Standard error = = Vp1(1-p1)/n1 + p2(1-p2)/n2 = V0.00038+0.000332 = 0.0222 = (p1-p2)+E = 0.06 +0.0436 = 0.1036

Confidence Interval = (0.0027,0.1173) Margin of error = 0.06 7 & 8) Given = x1 = 410 n1 = 1000 Now, Margin of error (E) = x2 = 315 n2 = 900 = Standard error * Za|2 p1 = x1/ni = 410 / 1000 = 0.4100 p2 = x2/n2 = 315 / 900 = 0.3500 = 0.0222*2.5758 = 0.0573 Therefore a) lower limit = 2.576 At 99% CI level = 222 = Here, p1-p2 = = 0.41-0.35 0.0600 = (p1-p2)-E = 0.06 -0.0573 = 0.0027 b) upper limits Standard error = = Vp1(1-p1)/n1 +p2(1-p2)/n2 = V0.00038+0.000332 0.0222 = (p1-p2)+E = 0.06 +0.0573 = 0.1173