Question

ANSWER

Country Financial, a financial services company, uses surveys of adults age 18 and older to determine if personal financial fitness is changing over time (USA Today, April 4, 2012). In February of 2012, a sample of 1000 adults showed 410 indicating that their financial security was more than fair. In February of 2010, a sample of 900 adults showed 315 indicating that their financial security was more than fair. a. State the hypotheses that can be used to test for a significant difference between the population proportions for the two years. H : Pi - P2 - Select your answer HA : P1 P2 - Select your answer - b. What is the sample proportion indicating that their financial security was more than fair in 2012? Round your answer to two decimal places. In 2010? Round your answer to two decimal places. C. Conduct the hypothesis test and compute the p-value. Round your answer to four decimal places. p-value = * At a = .05 level of significance, what is your conclusion? The input in the box below will not be graded, but may be reviewed and considered by your instructor. blank d. What is the 95% confidence interval estimate of the difference between the two population proportions? Round your answers to four decimal places. 95% confidence Interval to e. Based on your conclusion of the previous question, can you say the population proportion of adults saying that their financial security is more than fair has increased or decreased? - Select your answer - 7

Answer 1

b) The null and alternative hypothesis are: Ho: P.-P₂ = 0 Haip, -P₂70 This is a Two Failed Test. The sample proportion indicating that their financial security was more than fair in 2012 is, x = 410 mi - 1000 . . - x = 410 = 0.410 The sample proportion indicating that their financial security was more than fair in 2010 is, X=315 na=900 .. Poza 2 318 0.35 1000 900 c) pooled proportion, p = x+22 4 10+ 315 1000 + 900 725 1900 = o. 3815 7894736 = 0.3816

The rest statistic in, Z = PCI-E) ( + + - + 0.410 – 0.35 26.3816) (1-0.3816) (1000 + 2 ) = 2.6881703 = 2.69 P-value = 2* Plz>2.69) = 0.007145 70.0071 Since p-value ca=0.05, ale reject the null hypothesis. There is a significant difference between population proport of two years at 5% significance level a) The a5% confidence interval is, (6 - P2 ) & Zal_* Torino) (2 + 2) &= 1-0.95= 0.05 u. Zane Zorc= 1.96 (from Z-lable] 2 (0.41 -0.35) = 1.96* (0.3816) (10.3816) (1000 + 200 ) 0.06 +0.0437 - (0.0163, 0.1307) e) No, we can say because we can only & say population proportion of financial recurity is different, aas alternative hypothesis is two lailed which just indicates whether increared or decreased.

Answer 2

The P-Value is .0072

Answer 3

my answer was correct at p value 0.0071 though however, upper interval was 0.1037 so (.0163 to 0.1037)