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(1) Assume that the retaining wall shown in Fig. 1 can yield sufficiently to develop an active state. Determine the Rankine a

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-20/ka q= 15 kolm² Ant 5.415 kPa 30 120.376 25.9928 Pa V = 19 kolm? (Kal) 8 = 28, G=0 ------- -- 8 = 22 kN lm? 0= 34 (i=0 c Pa = 25.992 kolmen (6) Jost below 3m depth. Ou= 9+8, H, = 72 kN/m² I et Pakar Su-27 Skal at = (o. 283x72) = 20.376 kilm? I atI= Parchi & Pazhe Pait Par 3 -7.172m h = 6+ 25.992 + 2X5.415 1 25-992 +5.415 ₂ = ( 40.752 + 2x 20.376 = 1.33m [ 40.752 +20.37

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