Question

Practice Problem #3 For the retaining wall shown in Figure 13.19a, determine the force per unit length of the wall for Rankine's active state. Also find the location of the resultant. y = 16 kN/m = 30 d' = 0 Groundwater table Y = 18 kNm = 35° 0% = 7zK, -20'/K. 20

Which solution is correct the question is same

Answer 1

Solution- Given data Kankine active pressure pa orva ra'z Yzkae Zc'JEa kq:tant (45-412) v=GKNI33 BM Q=30 Cz0kp1=tan? (ts=302) = 3M Vsat 4=35°, cz0, każ=ten (t5-35/2)=0-27 for oa'= 16x0x for z=3 M Ltuotgh} Ta'=16x3xf=2 =16kPa- a =16x3X0.7=12.96kPa ( Just 3Mt) al= [icx3+C18-K3.2738 for t9.81x3 49.02 KPq

12 96ER 16KPa Fi b9.62kPa Resultaut force Fit x(49.02+12.96)x3 Fiこ 9297eNIm 2x12.967L.02 ** 12:96+49.02 Fzzx lex3 こ24kwlm = 3+ 3x Resultant force F=9297+29 F= l16.97kNM FiG, +FzyZ Fit Fz 92:97x1-21+24x4 location 92.97 +24 =1.78M Note',- I think this is the correcT. answer.