![2 Bru (g) = Brz (g) +4 () , Ke - 0.143 Molarity of Brg (g) = Molarity of tz(g) = 1.34 moles = 0.122 mote or M lle Brç (9) + «](//img.homeworklib.com/questions/5cd70340-b07f-11ea-a0ef-850a3040fa03.png?x-oss-process=image/resize,w_560)
![2 2 1/6,993 0,122-X -4.41 + 2.64 2K 0,122-1 21 0,112 0 322 - 2,644,2k -0,322 +2.64% z 2% -0.322 > 22-2-22 -0.322Ek 03322Ek 4,](//img.homeworklib.com/questions/5d56b200-b07f-11ea-a6e9-d151b9b219eb.png?x-oss-process=image/resize,w_560)
![Quest) 2 NO2 (g) + O2(g) = 2 N0 g), Re 04205 Ab tot 0.05 mole 0.122 mole 0.3 mole le Te J randem time (Not equilibrium time)](//img.homeworklib.com/questions/5de10800-b07f-11ea-99a0-993072edb210.png?x-oss-process=image/resize,w_560)
2 Bru (g) = Brz (g) +4 () , Ke - 0.143 Molarity of Brg (g) = Molarity of tz(g) = 1.34 moles = 0.122 mote or M lle Brç (9) + «x (9) . 0.122M 0-122M = 2 Brugge , ķ I . 26.993 0143 . Ab tao (Initial) -RM - KM + 20 M At (01122-2)M (0. 122-2) M ta tee + 22 M. 6.993 - [ Brceg)12 L2 (2x)2 Ebrz G3]'{44 (9]' (02122-23' (0.122-si
2 2 1/6,993 0,122-X -4.41 + 2.64 2K 0,122-1 21 0,112 0 322 - 2,644,2k -0,322 +2.64% z 2% -0.322 > 22-2-22 -0.322Ek 03322Ek 4,64 100089 = = 09502 = 1 % Niest possible an [242] [41] - 0.122-2 (becomes negative) də, [Brz (9) 7 °Cų (,) 2 - 0.122-0.019 M 20.053M Coru (g)] ex0.064 20,138M A 4. a) leven - above 2 N00g) = Nz (g) + O₂(g) keq - 3,5810-6 Multiply the reaction by 3 on both the sides and then reverse it we get 3N₂ (g) + 3O₂(g) = 6 NO(g), Kege 1 گراتن ؟ LE 22233*1,16
Quest) 2 NO2 (g) + O2(g) = 2 N0 g), Re 04205 Ab tot 0.05 mole 0.122 mole 0.3 mole le Te J randem time (Not equilibrium time) Let's find reaction duotient Corresponding to the above cencentration og species [NO3 (9)] -= 100392 de [NO, (97]4[Oz(9)]2 (0.059²x10.112)' reaction 295.082. quotient eit in terms of Concentration . (it is a tool to odentify the direction of reaction) hice de > ke z The reaction will proceed Apontaneous towards left by te that .