Question

please help!

6:117 Search .. LED x Equilibrium worksheet (3).pdf ... 7 of 8 3. What is the equilibrium constant expression for the action 2 Fe(s) + 2 NO 2 NO . 2 FO. Ans: K NO NO2 brum constante for the reaction b. What is the numerical value of the 2 503 al 2 502 .02 the equilibrium constant for the reaction given below is is 27x103 12 Oz gl. SO S OS Se A 4. A mixture of 3.31 moes of A 4,33 moles of Band 59 m continerala crtain peature. The reaction was allowed t number of moles of Bis 6.16. Calculate the equilibrium congan, K A ) 3 2 14105 o is placed in a oner h e Alb um, the orh o n Ans x 10

Answer 1

To solve the first question we need to understand few things:

1. The expression for equilibrium constant include only aqueous, liquid and gaseous substance only. We don't include solid.
2. If we change the molarity of the equation, the equilibrium constant is raised to the same power.

@ (a) the forewozula fore esce lë breerim constant for a recactrim : all + bB C + dD. | Ka [C] (P2? | (B),(200)Concentreation i (A7a (B) | a,b,c, d = mdarity aq / tiquid] where Here the equation is : Ofe (s) + 2NO,G) = onogg) + 2 fe 06). we will not include solid state reactants and preoducts ce fe of fel. so. Ale to above formule, the required expiression is : Keq e [arog/ cng y? I cans). 06 eq: K = ax 250,4)= 260,69) + 039) 72029) + sogg) = solg) K2 = 2.74103. corrept: BEA K'z yx /24 %2B K"=5K 2 2 2B K" = x² Lyon Man K". The so. Ki s z :/K3) 2= 7 (2.2 X10 -3) 2 148105 = 0.137 X1OC Hence, the Answere is 14X105.

It was a pleasure answering your questions. Hope this helps...

Good luck!!