Question

In Example 2.12, two circus performers rehearse a trick in which a ball and a dart collide. Horatio stands on a platform 9.6 m above the ground and drops a ball straight down. At the same moment, Amelia uses a spring-loaded device on the ground to launch a dart straight up toward the ball. The dart is launched at 12.4 m/s. Find the time and height of the collision by simultaneously solving the equations for the ball and the dart. (Due to the nature of this problem, do not use rounded intermediate values in your calculations—including answers submitted in WebAssign.) time s height m

Answer 1

9.6-X 9.6m 2 124m/s. Let the distance of collision from ground=a. The distance from platform = 9.6-X Now for falling body, u=0 a= 9.8m/s² let time of collision - t. using Equation of motion : s=ut that? for a 9.6-2 - ₃ x 9.8t² ) B. :- x= 12.4 t - 1 x 9.8 t 2 - ii) Adding (i) 8 ) we get for 9.6 = 12.4t t = get = 0.7745 Now. 06-x = 9.6 x = I x 9.8 X 9.6 x 9.6 2 x 12.4 12.4 gub n = 2.94 m x = 6.66 m Labove ground)