Question

13% O 10:55 Grade: 1.6/10 Print Version On average, indoor cats live to 13 years old with a standard deviation of 2.4 years. Suppose that the distribution is normal. Let X the age at death of a randomly selected indoor cat. Round answers to 4 decimal places where possible. what is the distribution of X? X N a. b. Find the probability that an indoor cat dies when it is between 15 and 16.7 years old. c. The middle 20 % of indoor cats' age of death lies between what two numbers? Low: years High: years Hint: Helpful videos: P(x< a number) P(x> a number) P(x is between two numbers) Finding a percentile Using the invNormal with greater than problems Finding the IQR . Hint Points possible: 1 Unlimited attempts. License II

Answer 1

Hello Sir/ Mam

Given that:

Mean = 13

S.D. = 2.4

WE denote normal Distribution as N(Mean, Variance)

Hence,

(a)

N(13,5.76)

(b)

We know that:

$P(15\leq X \leq 16.7)=P(X \leq 16.7)-P(X \leq 15)$

$P(15\leq X \leq 16.7)=93.84\%-79.77\%=0.1407$

(c)

Middle 20% is indicated by p-values of 0.4 and 0.6

and hence,

Low value = 12.39

High Value = 13.61

I hope this solves your doubt.

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