Homework Answers
3 Na (s) + Al+3 (aq) ----------> 3 Na+ (aq) + Al (s)
Sn+2 (aq) + 2 Fe+3 (aq) ---------> Sn+4 (aq) + 2 Fe+2 (aq)
2 Cr+3 (aq) + 6 Cl- (aq) ---------> 3 Cl2 (g) + 2 Cr (s)
Identify the change in oxidation numbers, which atom/ion is oxidized and which atom/ion is reduced and the number of electrons transferred. Now balance the charge on both sides accordingly.
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Reduce Simple Redux Equation
This method of balancing reaction is called the half reaction method. Balance...
Given the following list of half-reaction reduction potentials, identify the reaction that will occur spontaneously as...
Given the following list of half-reaction reduction potentials, identify the reaction that will occur spontaneously as written: Half-reaction E° (V) -0.74 Cr3+ (aq) + 3 e ---> Cr (s) Sn4+ (aq) + 2 e ---> Sn2+ (aq) +0.154 -0.440 Fe2+ (aq) + 2 e ---> Fe(s) Fe3+ (aq) + e ---> Fe2+ (aq) +0.771 2 Cr (s) + 3 Fe2+ (aq) ---> 3 Fe (s) + 2 Cr3+ (aq) 2 Cr3+ (aq) + 3 Sn2+ (aq) ---> 3 Sn4+ (aq)...
Half-reaction Cr3+ (aq) + 3e- → Cr(s) Fe2+ (aq) + 2e- → Fe (s) Fe3+ (aq) + e- + Fe2+ (s) Sn4+ (aq) + 2e- + Sn2+ (aq...
Half-reaction Cr3+ (aq) + 3e- → Cr(s) Fe2+ (aq) + 2e- → Fe (s) Fe3+ (aq) + e- + Fe2+ (s) Sn4+ (aq) + 2e- + Sn2+ (aq) E° (V) -0.74 -0.440 +0.771 +0.154 3Sn** (aq) +2Cr(s) → 2Cr** (aq) +3Sn²+ (aq) 3. What is the cell potential, Ecell, for the reaction above if [Sn] = 1.00 M, [Cr3+1 = 0.0200 M and [Sn2+] = 0.0100 M?
4. Use the table below to provide a redox reaction involving the spontaneous oxidation of Cr...
4. Use the table below to provide a redox reaction involving the spontaneous oxidation of Cr (balance your final reaction and provide the Ecell). Half-reaction E (V) Cr3+ (aq) + 3e Cr(s) -0.74 Fe(s) -0.440 Fe3+ (aq) + → Fe2+ (s) +0.771 Sn4+ (aq) + 2e Sn2+ (aq) +0.154 Fe2+ (aq) + 2e-
1. Balance the following using either method of balancing redox equations. Sn2+ + Cr,0,2 > Sn"+...
1. Balance the following using either method of balancing redox equations. Sn2+ + Cr,0,2 > Sn"+ + Cr3+ (acid solution) DO osoba (rotulosban Ag,0 + CH,0 -> Ag + HCO," (basic solution) On 60405
1. Balance the following redox reaction using the method of half-reactions (also called the ion-electron method)....
1. Balance the following redox reaction using the method of half-reactions (also called the ion-electron method). Mn2+ (aq) + NaBiO3 (s) → Bi3+ (aq) + MnO4- (aq) + Na+ (aq) 2. Balance the following reaction is basic media. (remember you should have no H+ ions in your final reaction.) Pb(OH)42- (aq) + ClO- (aq) → PbO2 (s) + Cl- (aq)
Relative Half-Cell Potentials Assuming standard conditions, answer the following questions. (Use the table of Standard Reduction...
Relative Half-Cell Potentials Assuming standard conditions, answer the following questions. (Use the table of Standard Reduction Potentials for common Half-reactions from your text. If hydrogen is one of the reagents, assume acidic solution.) cf Table 11.1 on p 403 of Zumdahl 8th ed. D y Is Fe2+ (aq) capable of oxidizing Cr metal? Is Ag+ (aq) capable of oxidizing H2(g)? Is Cr3+ (aq) capable of oxidizing Fe2+(aq) to Fe3+ (aq)? Is Cr3+ (aq) capable of oxidizing Fe2+(aq)? Is Fe3+(aq) capable...
Half-reaction Cr3+ (aq) + 3e--Cr(s) Fe2+ (aq) + 2e - Fe(s) Fe3+ (aq) - Fe2+ (5)...
Half-reaction Cr3+ (aq) + 3e--Cr(s) Fe2+ (aq) + 2e - Fe(s) Fe3+ (aq) - Fe2+ (5) Sn+ (aq) + 2e - Sn2(aq) E (V) -0.74 -0.440 +0.771 +0.154 1. Calculate the standard cell potential for the voltaic cell based on the reaction below, given the table above: 35nt(s) + 2Cr (s) - 2 C (s) + 3 Sn () ANSWER: 2. Calculate the standard cell potential for the voltaic cell based on the reaction below, Riven the table above 3Feb...
A. Half-reaction E° (V) Cl2(g) + 2e-2Cl-(aq) 1.360V Sn2+(aq) + 2e-Sn(s) -0.140V Cr3+(aq) + 3e-Cr(s) -0.740V...
A. Half-reaction E° (V) Cl2(g) + 2e-2Cl-(aq) 1.360V Sn2+(aq) + 2e-Sn(s) -0.140V Cr3+(aq) + 3e-Cr(s) -0.740V (1) The strongest oxidizing agent is: enter formula (2) The weakest oxidizing agent is: (3) The weakest reducing agent is: (4) The strongest reducing agent is: (5) Will Cl2(g) oxidize Cr(s) to Cr3+(aq)? (6) Which species can be oxidized by Sn2+(aq)? If none, leave box blank. B. Half-reaction E° (V) Cl2(g) + 2e-2Cl-(aq) 1.360V Cu2+(aq) + 2e-Cu(s) 0.337V Mn2+(aq) + 2e-Mn(s) -1.180V (1) The...
balance the following redox reactions in acidic solution by the half reaction method. Indicate which half...
balance the following redox reactions in acidic solution by the
half reaction method. Indicate which half reaction is for oxidation
and which for reduction.
b) Cr2O72- (aq) + CH(aq) > Cr*(aq) + Cl2(g) c) Au(s) + HNO3(aq) + HCl(aq) --> AuCl4- (aq) + NO(g) d) 103-(aq) + (aq) --> 13-(aq)
A) Use tabulated electrode potentials to calculate ΔG∘ for the reaction. 2K(s)+2H2O(l)→H2(g)+2OH−(aq)+2K+(aq) B) (Refer to the...
A) Use tabulated electrode potentials to calculate ΔG∘ for the reaction. 2K(s)+2H2O(l)→H2(g)+2OH−(aq)+2K+(aq) B) (Refer to the following standard reduction half-cell potentials at 25∘C: VO2+(aq)+Ni2+(aq)2H+(aq)++2e−e−→ →Ni(s)VO2+(aq) +H2O(l)E∘=−0.23V E∘=0.99V) An electrochemical cell is based on these two half-reactions: Oxidation:Reduction:Ni(s)VO2+(aq,0.024M)+2H+(aq,1.4M)+e−→→Ni2+(aq,1.8M)+2e−VO2+(aq,1.8M)+H2O(l) Calculate the cell potential under these nonstandard concentrations. C) Standard reduction half-cell potentials at 25∘C Half-reaction E∘ (V ) Half-reaction E∘ (V ) Au3+(aq)+3e−→Au(s) 1.50 Fe2+(aq)+2e−→Fe(s) − 0.45 Ag+(aq)+e−→Ag(s) 0.80 Cr3+(aq)+e−→Cr2+(aq) − 0.50 Fe3+(aq)+3e−→Fe2+(aq) 0.77 Cr3+(aq)+3e−→Cr(s) − 0.73 Cu+(aq)+e−→Cu(s) 0.52 Zn2+(aq)+2e−→Zn(s) − 0.76...
Given the following list of half-reaction reduction potentials, identify the reaction that will occur spontaneously as written: Half-reaction E° (V) -0.74 Cr3+ (aq) + 3 e ---> Cr (s) Sn4+ (aq) + 2 e ---> Sn2+ (aq) +0.154 -0.440 Fe2+ (aq) + 2 e ---> Fe(s) Fe3+ (aq) + e ---> Fe2+ (aq) +0.771 2 Cr (s) + 3 Fe2+ (aq) ---> 3 Fe (s) + 2 Cr3+ (aq) 2 Cr3+ (aq) + 3 Sn2+ (aq) ---> 3 Sn4+ (aq)...
Half-reaction Cr3+ (aq) + 3e- → Cr(s) Fe2+ (aq) + 2e- → Fe (s) Fe3+ (aq) + e- + Fe2+ (s) Sn4+ (aq) + 2e- + Sn2+ (aq) E° (V) -0.74 -0.440 +0.771 +0.154 3Sn** (aq) +2Cr(s) → 2Cr** (aq) +3Sn²+ (aq) 3. What is the cell potential, Ecell, for the reaction above if [Sn] = 1.00 M, [Cr3+1 = 0.0200 M and [Sn2+] = 0.0100 M?
4. Use the table below to provide a redox reaction involving the spontaneous oxidation of Cr (balance your final reaction and provide the Ecell). Half-reaction E (V) Cr3+ (aq) + 3e Cr(s) -0.74 Fe(s) -0.440 Fe3+ (aq) + → Fe2+ (s) +0.771 Sn4+ (aq) + 2e Sn2+ (aq) +0.154 Fe2+ (aq) + 2e-
1. Balance the following using either method of balancing redox equations. Sn2+ + Cr,0,2 > Sn"+ + Cr3+ (acid solution) DO osoba (rotulosban Ag,0 + CH,0 -> Ag + HCO," (basic solution) On 60405
Relative Half-Cell Potentials Assuming standard conditions, answer the following questions. (Use the table of Standard Reduction Potentials for common Half-reactions from your text. If hydrogen is one of the reagents, assume acidic solution.) cf Table 11.1 on p 403 of Zumdahl 8th ed. D y Is Fe2+ (aq) capable of oxidizing Cr metal? Is Ag+ (aq) capable of oxidizing H2(g)? Is Cr3+ (aq) capable of oxidizing Fe2+(aq) to Fe3+ (aq)? Is Cr3+ (aq) capable of oxidizing Fe2+(aq)? Is Fe3+(aq) capable...
Half-reaction Cr3+ (aq) + 3e--Cr(s) Fe2+ (aq) + 2e - Fe(s) Fe3+ (aq) - Fe2+ (5) Sn+ (aq) + 2e - Sn2(aq) E (V) -0.74 -0.440 +0.771 +0.154 1. Calculate the standard cell potential for the voltaic cell based on the reaction below, given the table above: 35nt(s) + 2Cr (s) - 2 C (s) + 3 Sn () ANSWER: 2. Calculate the standard cell potential for the voltaic cell based on the reaction below, Riven the table above 3Feb...
balance the following redox reactions in acidic solution by the
half reaction method. Indicate which half reaction is for oxidation
and which for reduction.
b) Cr2O72- (aq) + CH(aq) > Cr*(aq) + Cl2(g) c) Au(s) + HNO3(aq) + HCl(aq) --> AuCl4- (aq) + NO(g) d) 103-(aq) + (aq) --> 13-(aq)
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