Question

A) Use tabulated electrode potentials to calculate ΔG∘ for the reaction. 2K(s)+2H2O(l)→H2(g)+2OH−(aq)+2K+(aq) B) (Refer to the...

A)

Use tabulated electrode potentials to calculate ΔG∘ for the reaction.
2K(s)+2H2O(l)→H2(g)+2OH−(aq)+2K+(aq)

B)

(Refer to the following standard reduction half-cell potentials at 25∘C:

VO2+(aq)+Ni2+(aq)2H+(aq)++2e−e−→ →Ni(s)VO2+(aq) +H2O(l)E∘=−0.23V E∘=0.99V)

An electrochemical cell is based on these two half-reactions:

Oxidation:Reduction:Ni(s)VO2+(aq,0.024M)+2H+(aq,1.4M)+e−→→Ni2+(aq,1.8M)+2e−VO2+(aq,1.8M)+H2O(l)


Calculate the cell potential under these nonstandard concentrations.

C)

Standard reduction half-cell potentials at 25∘C

Half-reaction E∘ (V ) Half-reaction E∘ (V )
Au3+(aq)+3e−→Au(s) 1.50 Fe2+(aq)+2e−→Fe(s) − 0.45
Ag+(aq)+e−→Ag(s) 0.80 Cr3+(aq)+e−→Cr2+(aq) − 0.50
Fe3+(aq)+3e−→Fe2+(aq) 0.77 Cr3+(aq)+3e−→Cr(s) − 0.73
Cu+(aq)+e−→Cu(s) 0.52 Zn2+(aq)+2e−→Zn(s) − 0.76
Cu2+(aq)+2e−→Cu(s) 0.34 Mn2+(aq)+2e−→Mn(s) − 1.18
2H+(aq)+2e−→H2(g) 0.00 Al3+(aq)+3e−→Al(s) − 1.66
Fe3+(aq)+3e−→Fe(s) − 0.036 Mg2+(aq)+2e−→Mg(s) − 2.37
Pb2+(aq)+2e−→Pb(s) − 0.13 Na+(aq)+e−→Na(s) − 2.71
Sn2+(aq)+2e−→Sn(s) − 0.14 Ca2+(aq)+2e−→Ca(s) − 2.76
Ni2+(aq)+2e−→Ni(s) − 0.23 Ba2+(aq)+2e−→Ba(s) − 2.90
Co2+(aq)+2e−→Co(s) − 0.28 K+(aq)+e−→K(s) − 2.92
Cd2+(aq)+2e−→Cd(s) − 0.40 Li+(aq)+e−→Li(s) − 3.04

Use the tabulated electrode potentials to calculate K for the oxidation of zinc by H+:

Zn(s)+2H+(aq)→Zn2+(aq)+H2(g)

D)

Standard reduction half-cell potentials at 25∘C

Half-reaction E∘ (V ) Half-reaction E∘ (V )
Au3+(aq)+3e−→Au(s) 1.50 Fe2+(aq)+2e−→Fe(s) − 0.45
Ag+(aq)+e−→Ag(s) 0.80 Cr3+(aq)+e−→Cr2+(aq) − 0.50
Fe3+(aq)+3e−→Fe2+(aq) 0.77 Cr3+(aq)+3e−→Cr(s) − 0.73
Cu+(aq)+e−→Cu(s) 0.52 Zn2+(aq)+2e−→Zn(s) − 0.76
Cu2+(aq)+2e−→Cu(s) 0.34 Mn2+(aq)+2e−→Mn(s) − 1.18
2H+(aq)+2e−→H2(g) 0.00 Al3+(aq)+3e−→Al(s) − 1.66
Fe3+(aq)+3e−→Fe(s) − 0.036 Mg2+(aq)+2e−→Mg(s) − 2.37
Pb2+(aq)+2e−→Pb(s) − 0.13 Na+(aq)+e−→Na(s) − 2.71
Sn2+(aq)+2e−→Sn(s) − 0.14 Ca2+(aq)+2e−→Ca(s) − 2.76
Ni2+(aq)+2e−→Ni(s) − 0.23 Ba2+(aq)+2e−→Ba(s) − 2.90
Co2+(aq)+2e−→Co(s) − 0.28 K+(aq)+e−→K(s) − 2.92
Cd2+(aq)+2e−→Cd(s) − 0.40 Li+(aq)+e−→Li(s) − 3.04

Use tabulated standard electrode potentials to calculate the standard cell potential for the reaction occurring in an electrochemical cell at 25 ∘C. (The equation is balanced.)

Sn2+(aq)+Cd(s)→Sn(s)+Cd2+(aq)

E)

Balance the following redox reactions occurring in acidic aqueous solution.

MnO−4(aq)+Al(s) → Mn2+(aq)+Al3+(aq)

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