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Write the half reactions and overall reaction for each cell with calculated overall potentials as shown in Table 5-1. (Note:Cu() Cu(NO3)2(0.1M) Il Fe (0.1M/Fe? (0.1M graphite Pb(s) Pb(NO3)2(0.1M) Il Fe3(aq) (0.1M)/ Fe2(aq) (0.1MI graphite(s) Zns | ZIn this manner we can determine the relative cell potentials for any series of half-cells, such as those given in the followi

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Pb(s) (Pb(NO3), (0:1)||GCNOS):)| Cul) Cal Anode reaction РЬ - де. +2003 Pb(NO3)2 Cde Cathode E = 0.13V Cu(NO3)2 +2e Cu + 2NOGJuly 09 el . 21 Zn(9| En(NO3), (0:1) ffu(NO3X0-10 Anode reaction Zn-2e - Zn 20 +0.760 Cathode zgaction Tutae. Cu(s), E= 0.34July 09 Jul 22. Wednesday Cu foulave), 1.0.10/f relaylpeito CON Anode reaction Cathode reaction re 30 te ke 20 [EON Overall rJuly 09 23 Thursday Zn(9|7n(109) 2 (01)| Pune), (PLS Anode Zn-ae - Zn 2009 agitov Cathode, ভারতের সংবিধান Pb Pb 20 Pb, 0.13V

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