Question

if 5ml of 3.0 x10^-5 M crystal violet solution is mixed with 2ml of 0.1M of NaOH, what is the concentration of crystal violet in this solution?

CV+ (aq ) + OH− (aq) = CVOH (aq )

Answer 1

We use the relation M1V1 = M2V2

M1 = Molarity of crystal violet = 3 x 10^-5 M

V1 = Volume of crystal violet = 0.005 L = 0.005 L

M2 = Final molarity of solution = Unknown

V2 = Final volume = Volume of NaOH + Volume of crystal violet = 0.005 L + 0.002 L = 0.007 L

M2 = M1V1 / V2 = (3 x 10^-5 x0.005) / 0.007

M2 = 2.14 x 10^-5 M