a protein sample was diluted 1/5 and then 5ml of the diluted sample was mixed with...
a protein sample was diluted 1/5 and then 5ml of the diluted sample was mixed with 20 ml of reactants to give 25 ml total volume. from this 25 ml solution, 5ml were removed. this 5ml contain 3 mg of protein. what was the concentration of protein in the original sample
Homework Answers
5 ml of the sample has 3 mg protein.
Therefore the 25 ml solution on the whole contains 5*3mg of protein =15 mg of protein.
5 ml which was taken from 1/5th dilution contains 15 mg protein. Thus, the original sample should contain 5 times of 15 mg protein
=75 mg of protein.
Thus the original sample contains 75 mg of protein
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