ncetoi paper) 1. BSA stock solution A has a concentration of 3.50 mg/mL. 1.00 mL of...
4. (a) Determine the experimental concentration of protein in the unknown solution in mg/mL using the Part II Data Table and the equation on page 2 for the absorbance assay at 280 nm. Hint: Convert the molar concentration (M or moles/liter) of BSA from absorbance assay at 280 nm method to mg/mL, assume that the molecular weight of BSA = 66.5 kDa [7 points 6500 g/mol Post-lab 10 Report Form: Determination the Concentration of a Protein You must show your...
From a 2,000 μg/mL BSA stock, create 1 mL of each of the following stock solutions in 0.02 M phosphate buffer using individual microcentrifuge tubes: 50 μg/mL, 250 μg/mL, 500 μg/mL, 1,000 μg/mL, 1,250 μg/mL, 1,500 μg/mL. Calculate the volume of BSA stock that will be required to make the standard solutions needed to create the BSA standard curve. Be sure to show your work and include the volume of 0.02 M phosphate buffer required to reach a final volume...
1. Serial dilution Questions: a) (5 pts) Suppose you begin with stock solution of dye that has a concentration of 350.0 mg/L and do the following set of serial dilutions on it: 5.00 mL of stock diluted to a total volume (TV) of 500.00 mL (Dilution 1); 2.00 mL of Dilution 1 is then diluted to a TV of 250.00 mL (Dilution 2); finally, 1.00 mL of Dilution 2 is then diluted to a total volume of 100.00 mL. Calculate...
The initial concentration of a protein sample is 25 μg/μl. Calculate the volumes of the stock protein and water (diluent) necessary to prepare a 1:5 dilution in a final volume of 4 mL. What is the diluted concentration? Volume of Protein: Volume of Water: Resulting Concentration:
Suppose 5.00 mL of a 1.00 M stock solution is diluted to 25.00 mL. Afterwards, 5.00 mL of this solution is diluted to 25.00 mL. What is the concentration of the final solution?
Please show work: 1) Complete the calculations and fill in the missing volumes needed below to create a six-tube solute dilution series from a protein stock solution, 1.0 mg/ml BSA (bovine serum albumin) into 1.5 ml microcentrifuge tubes using CIVI = C2V2, note V2 is not 1.5ml. A table is provided below to record your efforts. New solutions Tube Concentration Volumes stock protein Dl water Final volume 1.00 mg/ml 250.0 ul 0.0 ul 250.0 ul 250.0 ul 0.80 mg/ml 0.60...
Given 37ul of a 100 mg/ml stock solution of Bovine Serum Albumin (BSA), diagram the most accurate procedure so you end up with at least 500ul each of 5ug/ul, 0.5 ug/ul, and 0.05 ug/ul working solutions of BSA.
BSA Standard (mg/mL) BSA Working Solution (0.5 mg/mL) ddH2O (µL) BSA Standard (µL) 1 x Bradford Reagent (µL) OD595nm Reading 0.00 0 500 25 975 0.00 0.025 25 475 25 975 0.43 0.05 50 450 25 975 0.45 0.1 100 400 25 975 0.469 0.15 150 350 25 975 0.571 0.2 200 300 25 975 0.621 0.3 300 200 25 975 0.638 0.4 400 100 25 975 0.713 1. Construct a standard curve and plot. 2. Your unknown sample yields...
1) Show the conversion between volume of stock and final concentration for one of the standards. Show all work and give the concentration and equations used. 2) Use the Lambert-Beer’s law equation to calculate the concentration of iron in your patient’s sample (Unknown B). Show all steps of your calculation. Based on the calculations from your experimental results, is the iron level in your patient’s blood too low or too high? 3) Explain in detail how you would treat your...
Serial Dilution Questions 1, Serial dilution Questions: a) (5 pts) Suppose you begin with stock solution of dye that has a concentration of 350.0 mg/L and do the following set of serial dilutions on it: 5.00 mL of stock diluted to a total volume (TV) of 500.00 mL (Dilution 1); 2,00 mL of Dilution 1 is then diluted to a TV of 250.00 mL (Dilution 2); finally, 1.00 mL of Dilution 2 is then diluted to a total volume of...