a | Frequency(O) | P(x<a) | P(interval) | Exp frequency(E) | (O-E)^2/E |
NORM.DIST(a,17.7,7.3,TRUE) | P(a)-P(a1) | P(interval)*203 | |||
10 | 25 | 0.1457597 | 0.14576 | 29.58921 | 0.711775 |
20 | 86 | 0.6236452 | 0.477886 | 97.01076 | 1.249726 |
30 | 72 | 0.9539991 | 0.330354 | 67.06185 | 0.363625 |
>30 | 20 | 1 | 0.046001 | 9.338181 | 12.17307 |
203 | 1 | 203 | 14.4982 | ||
df | 3 | (4-1) |
chi-square test statistic = 14.50
p value<0.01, two-tailed P value equals 0.0023
Reject Ho: there is enough evidence....
Consider the following sample data with mean and standard deviation of 177 and 7.3, respectively. (You...
You are given the following summary statistics from a sample of 26 observations: (You may find it useful to reference the appropriate table: chi-square table or F table) Mean 67.28 Standard Deviation 11.73 Skewness 1.11 Kurtosis 1.78 a. Using the Jarque-Bera test, specify the null and alternative hypotheses to determine whether or not the data are normally distributed. H0: S = 0 and K = 0; HA: S ≠ 0 and K ≠ 0 H0: S = 0 and K...
A manufacturer claims that the mean lifetime of its lithium batteries is less than 1095 hours. A homeowner selects 27 of these batteries and finds the mean lifetime to be 1065 hours with a standard deviation of 76 hours. Test the manufacturer's claim. Use a = 0.02. P-value = 0.112 > 0.02; do not reject H0; There is not enough evidence support the claim that mean is less than 1500. ОА P-value = 0.025 0.02, do not reject HO, There...
Chapter 12 Homework instructions | help Question 7 (of 7) Save & Exit Submit 7.value: 10.00 points Exercise 12-29 Algo Seventy four cities provided information on vacancy rates (in percent) in local apartments in the following frequency distribution. The sample mean and the sample standard deviation are 10% and 3.6%, respectively. Use Table 3. Vacancy Rate (in percent) Frequency Less than 6 6 6 up to 9 15 9 up to 12 32 12 or more 21 a. Choose the...
A random sample from normal population yielded sample mean=40.8 and sample standard deviation= 6.1, n = 15. H0: μ = 32.6, Ha: μ ≠ 32.6, α = 0.05. Perform the hypothesis test and draw your conclusion. Question 3 options: Test statistic: t = 5.21. P-value=0.00013. Reject H0. There is sufficient evidence to support the claim that the mean is different from 32.6. Test statistic: t = 5.21. P-value=1.9E-7 (0.00000019). Do not reject H0. There is not sufficient evidence to support...
A random sample from normal population yielded sample mean=40.8 and sample standard deviation= 6.1, n = 15. H0: μ = 32.6, Ha: μ ≠ 32.6, α = 0.05. Perform the hypothesis test and draw your conclusion. A. Test statistic: t = 5.21. P-value=0.00013. Reject H0. There is sufficient evidence to support the claim that the mean is different from 32.6. B. Test statistic: t = 5.21. P-value=1.9E-7 (0.00000019). Reject H0. There is sufficient evidence to support the claim that the...
A random sample of size ni = 30 yields a standard deviation of 8.5, and a random sample of size n2 = 31 yields a standard deviation of 6.6. At a = 0.01, test the claim that the standard deviation of Population 1 is not the standard deviation of Population 2. 1. The alternate hypothesis is Ha: Oo o 0917 02 Os s Osi #s2 2. This is a two tailed test with: dfn= and dfa - 3a. The STS...
In order to conduct a hypothesis test for the population mean, a random sample of 28 observations is drawn from a normally distributed population. The resulting sample mean and sample standard deviation are calculated as 17.9 and 1.5, respectively. (You may find it useful to reference the appropriate table: z table or t table). HO: MS 17.5 against HA: > 17.5 a-1. Calculate the value of the test statistic. (Round all intermediate calculations to at least 4 decimal places and...
1. Sample Mean: mens- 27.91 women - 31.57 2. Standard Deviation men- 0.664 women- 1.167 Sample Size mens- 32 womens- 35 Using the values that you found in numbers 1 and 2, perform the following hypothesis test. At a 10% significance level, test the claim that the women’s mean completion time is greater than ___________ (the men’s mean completion time). Ho: _________________ Ha: __________________ Label the claim. What type of test will you use? (Z-Test, T-test, or 1-ProZTest) ____________________ Where...
In order to conduct a hypothesis test for the population mean, a random sample of 14 observations is drawn from a normally distributed population. The resulting sample mean and sample standard deviation are calculated as 77 and 2.0, respectively. (You may find it useful to reference the appropriate table: z table or t table). =o: * $ 6.6 against N' > 6.6 2-1. Calculate the value of the test statistic (Round all intermediate calculations to at least 4 decimal places...
A random sample from normal population yielded sample mean=40.8 and sample standard deviation=6.1, n = 15. HO: u = 32.6, Haru # 32.6, a = 0.05. Perform the hypothesis test and draw your conclusion. Test statistic: t = 5.21. P-value=1.9E-7 (0.00000019). Reject Ho. There is sufficient evidence to support the claim that the mean is different from 32.6. Test statistic: t = 5.21. P-value=1.9E-7 (0.00000019). Do not reject HO. There is not sufficient evidence to support the claim that the...