Which of my answers are wrong? Previous Problem Problem List Next Problem (1 point) Select the...
(1 point) Select the FIRST correct reason why the given series converges. A. Convergent geometric series B. Convergent p series C. Comparison (or Limit Comparison) with a geometric or p series D. Alternating Series Test E. None of the above 1. n² + √n n4 – 4 sin?(2n) n2 E 4 (n + 1)(9)" n=1 2n + 2 cos(NT) 16. In(3n)
Aleast one of the answers above is NOT correct. (1 pt) Select the FIRST correct reason why the given series converges. AL A. Convergent geometric series B. Convergent p series C. Integral test D. Comparison with a convergent p series E. Converges by limit comparison test F. Converges by alternating series test 1. LG (cos(17) 2. X 1 In(70) 3. 722 | In(n) M1 72 g 7246 5. ( 1)" 116 (n. 11) (82 1)" | 821 Note: You are...
(1 point) Select the FIRST correct reason why the given series converges. A. Convergent geometric series B. Convergent p series C. Comparison with a geometric or p series D. Alternating Series Test E. None of the above 1. Cos(17) (ln(6n) (n + 1)(80)" (n + 2)92n n² | 6. § (-1)",
I have all of these correct except for 1, and I cant determine which it is. (2 points) Select the FIRST correct reason from the list below that explains why the given series converges A. Convergent geometric series B. Convergent p series C. Comparison (or Limit Comparison) with a geometric or p series D. Alternating Series Test E. Cannot apply any test done so far in class 4n+7 (15) MiMiM8 2 (n+1)42 o n² + √n n4 - 8 sin’(4n)...
(1 point) Select the FIRST correct reason on the list why the given series converges. D-1)", n 6 E 1 sin2 (3n) 2. n2 00 (п+ 1)(15)" 3. B 42n n-1 OC 6(6)" A 4. 2n 11 n 1 00 (-1)" In(e") п° cos(пт) C 5. n-1 1 D 6. п(m(n))? п-2 A. Geometric series B. Ratio test C. Integral test D. Comparison with a convergent p series. E. Alternating series test c2 (1 point) Select the FIRST correct reason...
(1 pt) Test each of the following series for convergence by either the Comparison Test or the Limit Comparison Test. If either test can be applied to the series, enter CONV if it converges or DIV If it diverges. If neither test can be applied to the series, enter NA. (Note: this means that even if you know a given series converges by some other test, but the comparison tests cannot be applied to it, then you must enter NA...
Series Practice: Problem 4 Previous Problem List Next (3 points) NOTE: Only 3 attempts are allowed for the whole problem Select the FIRST correct reason why the given series diverges. A. Diverges because the terms don't have limit zero B. Divergent geometric series C. Divergent p series D. Integral test E. Comparison with a divergent p series F. Diverges by limit comparison test G. Diverges by alternating series test 1.Zn) 2. o0_ ln(n) cos(nT) nIn(6) 4 Series Practice: Problem 4...
(1 point) For each of the series below select the letter from a to c that best applies and the letter from d to j that best applies. A possible correct answer is af, for example. A. The series is absolutely convergent. B. The series converges, but not absolutely C. The series diverges D. The alternating series test shows the series converges. E. The series is a p-series F. The series is a geometric series. G. We can decide whether...
IMIMIMIMIM Next BIO LIS (1 point) Match each of the following with the correct statement. A. The series is absolutely convergent. C. The series converges, but is not absolutely convergent. D. The series diverges. 00 (n+2)! 1. 7" n! (1) 2" n! 2. n=1 (-1)"2"-1 3. P=1 (2)+In 00 n! ΣΕ) 10" 00 n 5. 4" Note: In order to get credit for this problem all answers must be coIrect. Preview My Answers Submit Answers IMIMIMIMIM Next BIO LIS (1...
Previous Problem Problem List Next Problem 4n + (1 point) Use the limit comparison test to determine whether Ž. - converges 1412 p. converge or diverges. (a) Choose a series br with terms of the form bn = and apply the limit comparison test. Write your answer as a fully reduced fraction. For n > 14, lim = lim 1+00 1 00 (b) Evaluate the limit in the previous part. Enter op as infinity and -o as-infinity. If the limit...