Consider the folowing 2nd-order linear non-homogeneous DE, 1'- 12y' + 36y = 18c6x The complimentary solution...
Consider the differential equation: y" + 12y' + 36 = 6x2 + 5e-52. a. Find the general solution to the corresponding homogeneous equation. In your answer, use cy and ca to denote arbitrary constants. Enter C as c1 and ca as c2. Yc = b. Apply the method of undetermined coefficients to find a particular solution. Yp = Submit answer
We consider the non-homogeneous problem y' = 30(18x – 2x4) First we consider the homogeneous problem y'' = 0 : 1) the auxiliary equation is ar2 + br +c= = 0. 2) The roots of the auxiliary equation are (enter answers as a comma separated list). 3) A fundamental set of solutions is (enter answers as a comma separated list). Using these we obtain the the complementary solution yc = C1y1 + C2y2 for arbitrary constants ci and C2- Next...
(8 pts) In this problem you will solve the non-homogeneous differential equation y" + 9y = sec (3x) (1) Let C and C2 be arbitrary constants. The general solution to the related homogeneous differential equation y" + 9y = 0 is the function yn (x) = C1 yı(2) + C2 y2(x) = C1 +C2 NOTE: The order in which you enter the answers is important; that is, Cif(x) + C2g(x) + C19(x) + C2 f(x). (2) The particular solution yp(x)...
(1 point) We consider the non-homogeneous problem y" – y'=1 – 10 cos(2x) First we consider the homogeneous problem y" – y' = 0; 1) the auxiliary equation is ar? + br +c= = 0 2) The roots of the auxiliary equation are (enter answers as a comma separated list). (enter answers as a comma separated list). Using these we obtain the the complementary solution yc = Ciyi + C2y2 for arbitrary 3) A fundamental set of solutions is constants...
5) Consider the second order linear non-homogeneous differential equation tay" - 2y = 3t2 - 1,t> 0. a) Verify that y(t) = t- and y(t) = t-1 satisfy the associated homogeneous equation tay" - 2y = 0. (5 points) b) Find a particular solution to the non-homogeneous differential equation. (10 points) c) Find the general solution to the non-homogeneous differential equation. (5 points)
(1 point) We consider the non-homogeneous problem y" - y' = -4 cos(x) First we consider the homogeneous problem y -y = 0 : = 0 1) the auxiliary equation is ar2 + br + c = 2) The roots of the auxiliary equation are (enter answers as a comma separated list) 3) A fundamental set of solutions is (enter answers as a comma separated list). Using these we obtain the the complementary solution ye = ciyı + c2y2 for...
(1 point) We consider the non-homogeneous problem y" + 4y = -32(3x + 1) First we consider the homogeneous problem y" + 4y = 0: 1) the auxiliary equation is ar? + br +c= r^2+4r = 0. 2) The roots of the auxiliary equation are 0,4 (enter answers as a comma separated list). (enter answers as a comma separated list). Using these we obtain the the complementary 3) A fundamental set of solutions is 1,e^(-4x) solution yc = cyı +...
(1 point) We consider the non-homogeneous problem y" +2y +2y 20os(2x) First we consider the homogeneous problem y" + 2y' +2y 0 1) the auxiliary equation is ar2 br 2-2r+2 2) The roots of the auxiliary equation are i 3) A fundamental set of solutions is eAxcosx,e xsinx (enter answers as a comma separated list). (enter answers as a comma separated list). Using these we obtain the the complementary solution yc-c1Y1 + c2y2 for arbitrary constants c1 and c2. Next...
Consider the following 2nd order nonhomogeneous linear equation x 00 + 4x 0 + 5x = cos 2t 1. Solve for the fundamental solutions of its associated homogeneous equation. 2. Find a particular solution of the nonhomogeneous equation. 3. Based on your answer to the previous two questions, write down the general solution of the nonhomogeneous equation. Problem II (15 points) Consider the following 2nd order nonhomogeneous linear equation x" + 40' + 5x = cos 2t 1. (6 points)...
The general solution of the first order non-homogeneous linear differential equation with variable coefficients \((x+1) \frac{d y}{d x}+x y=e^{-x}, \quad x>-1 \quad\) equalsQ \(y=e^{-x}\left[C\left(x^{2}-1\right)+1\right]\), where \(C\) is an arbitrary constant.None of themQ \(y=e^{x}\left[C\left(x^{2}-1\right)+1\right]\), where \(C\) is an arbitrary constant.\(y=e^{-x}[C(x+1)-1]\), where \(C\) is an arbitrary constant.\(y=e^{x}[C(x-1)+1]\), where \(C\) is an arbitrary constant.