The general solution of the first order non-homogeneous linear differential equation with variable coefficients \((x+1) \frac{d y}{d x}+x y=e^{-x}, \quad x>-1 \quad\) equals
Q \(y=e^{-x}\left[C\left(x^{2}-1\right)+1\right]\), where \(C\) is an arbitrary constant.
None of them
Q \(y=e^{x}\left[C\left(x^{2}-1\right)+1\right]\), where \(C\) is an arbitrary constant.
\(y=e^{-x}[C(x+1)-1]\), where \(C\) is an arbitrary constant.
\(y=e^{x}[C(x-1)+1]\), where \(C\) is an arbitrary constant.
The general solution of the first order non-homogeneous linear differential equation with variable coefficients
The general solution of the first order non homogeneous linear differential equation with variable dy coefficients (x+1)+zy=e" => -1 equals None of them Oy =é (C(x - 1) + 1), where is an arbitrary constant. Oy=é (C(ZP – 1) + 1). where is an arbitrary constant. Oy=e*10*? - 1) + 1]. where is an arbitrary constart Oy=-*|C(2+1) – 1), where is an arbitrary constant
The general solution of the first order non-homogeneous linear differential dy equation with variable coefficients (x + 1) + xy=e, I > -1 equals dx Oy=e-* [C(x2 - 1) + 1], where is an arbitrary constant. None of them Oy=e* [C(x2 – 1) +1], where is an arbitrary constant. yre *(C(x + 1) - 1], where is an arbitrary constant. Oy=e" (C(x - 1) + 1], where is an arbitrary constant.
Question 2 3 pts The general solution of the first order non-homogeneous linear differential dy equation with variable coefficients (x + 1) + xy = e-, x>-1 dx equals y=e-* (C(x + 1) - 1], where C is an arbitrary constant. Oy=e" (C(x - 1) + 1], where is an arbitrary constant. Oy=e" (C(x2 – 1) + 1], where C is an arbitrary constant. None of them O y=e" (C(x2 – 1) +1], where C is an arbitrary constant.
Question 1 3 pts The solution of the Initial-Value Problem (IVP) S (x + y)dx – «dy = 0 is given by 1 y(1) = 0 Oy=det-1 - 1 Oy= < ln(x + y) Oy= (x + y) In x Oy= < In x None of them Question 2 3 pts The general solution of the first order non-homogeneous linear differential equation with variable coefficients dy (x + 1) + xy = e-">-1 equals dx 2 Oy=e* (C(x - 1)...
Зрт Question 1 f (x + y)da - ady=0 The solution of the Initial-Value Problem (IVP) 1 y(1) = 0 is given by Oy= (x + y) In a Oy = x In a Oy= « ln(x + y) 3 = teº-1 None of them n Question 2 3 pts The general solution of the first order non-homogeneous linear differential equation with variable dy coefficients (a +1) + xy = e > -1 equals da 3 Oy= e-* [C(x2 -...
Find a second order linear equation L(y) = f(t) with constant coefficients whose general solution is: @ y=Cje24 + C261 + te3t @ (a) The solution contains three parts, so it must come from a nonhomogeneous equation. Using the two terms with undefined constant coefficients, find the characteristic equation for the homogeneous equation. (b) Using the characteristic equation find the homogeneous differential equation. This should be the L(y) we're looking for. (c) Since we have used two terms from the...
2. (e) (7 points) Find a homogeneous linear differential equation with constant coefficients whose general solution is y = 4 + ce?* + Gxe7x.
Problem 1 (14 points) (a) Find the general solution to a third-order linear homogeneous differential equation for y(1) with real numbers as coefficients if two linearly independent solutions are known to be e-21 and sin(3.c). e (b) Determine that differential equation described in part (a).
Problem 1 (14 points) (a) Find the general solution to a third-order linear homogeneous differential equation for y(1) with real numbers as coefficients if two linearly independent solutions are known to be e-21 and sin(3.c). e (b) Determine that differential equation described in part (a).
Consider the folowing 2nd-order linear non-homogeneous DE, 1'- 12y' + 36y = 18c6x The complimentary solution of the equation is Yo (x) = where ci and C2 are arbitrary constants. A particular solution of the equation is yp (x) = 1 The general solution of the non-homogeneus equation is y(x) = symbolic formatting help Consider the following 2nd-order linear non-homogeneous DE, y" – 20y' + 100y = (2x + 14) 207 The complimentary solution of the equation is y. (x)...