Cucurung an equilibrium constant from a heterogeneou! Calcium carbonate decomposes to form calcium oxide and carbon...
Calcium oxide and carbon dioxide react to form calcium carbonate, like this: CaO(s)+CO,(g)→ CaCO3(s) At a certain temperature, a chemist finds that a 2.5 L reaction vessel containing a mixture of calcium oxide, carbon dioxide, and calcium carbonate at equilibrium has the following composition: compound amount CaO | 20.5 g CO2 17.1 g CaCo3 66.7 g Calculate the value of the equilibrium constant K for this reaction. Round your answer to 2 significant digits. K = 0 xs ?
QUESTION 3 Solid calcium carbonate (CaCO3) decomposes into solid calcium oxide (Cao) and carbon dioxide (CO) gas according to the following heterogeneous equilibrium: CaCO3(s) = Cao(s) + CO2(g) What is the correct equilibrium constant expression for this equation? OK (CaCO3] [Cao][CO2] ok, = [Coz] [Cao][CO.” [CaCO3] okea 0K = [Cao][CO2] [Ca][CO] (CaCO3] ok
help please! thnx 4. Consider the equilibrium in which solid calcium carbonate decomposes to the oxide plus carbon dioxide CaCO3(s) CaO(s) + CO2(g) Write down an expression for the equilibrium constant of this reaction in terms of the partial pressure of CO2. The standard enthalpies of formation of CaCO3(s), CO2(g) and CaO(s) are -1207.6 kJ mol", -393.5 kJ mol' and -634.9 kJ mol? respectively, and the standard entropies are 91.7JK'mol, 213.8JK' mol and 38.1 J K mol' (all at 298...
A.) When heated, calcium carbonate decomposes to yield calcium oxide and carbon dioxide gas via the reaction CaCO3(s)→CaO(s)+CO2(g) What is the mass of calcium carbonate needed to produce 25.0 L of carbon dioxide at STP? B.) Butane, C4H10, is a component of natural gas that is used as fuel for cigarette lighters. The balanced equation of the complete combustion of butane is 2C4H10(g)+13O2(g)→8CO2(g)+10H2O(l) At 1.00 atm and 23 ∘C, what is the volume of carbon dioxide formed by the combustion...
At high temperatures calcium carbonate decomposes into calcium oxide and carbon dioxide. CaCO3 (solid) {> Cao (solid) + CO2 (gas) Find the equilibrium pressure of this system at 1200 K if the equilibrium constant at 1400 K is 26. If the AGº of CaO(solid) and CaCO3 (solid) at 298 Kare -604 and -1128.8 kJ/mol respectively, estimate the equilibrium constant Kat 298 K and the equilibrium pressure. Discuss the effect of pressure on both the conversion of CaCO3 and the final...
When heated, calcium carbonate decomposes to yield calcium oxide and carbon dioxide gas via the reaction CaCO3 ---> CaO + CO2 How many grams of calcium carbonate are needed to produce 73.0 of carbon dioxide at STP?
CaCO3(s) = Cao (s)+CO2 (g) When heated strongly, solid calcium carbonate decomposes to produce solid calcium oxide and carbon dioxide gas, as represented by the equation above. A 2.0 mol sample of CaCO3(s) is placed in a rigid 100. L reaction vessel from which all the air has been evacuated. The vessel is heated to 898°C at which time the pressure of CO2(g) in the vessel is constant at 1.00 atm, while some CaCO3(s) remains in the vessel. a. Calculate...
Calcium oxide (lime) reacts with carbon dioxide to form calcium carbonate (chalk). CaO(s) + CO2(g) → CaCO3(s) ∆H = –178.4 kJ How many kilojoules of heat are evolved in the reaction of 0.500 kg CaO(s) (molar mass 56.08 g/mol) with an excess of carbon dioxide?
At 1073 K, the equilibrium pressure of carbon dioxide above mixtures of calcium carbonate and calcium oxide is 183 torr. (a) If 5.0 g of solid calcium carbonate is placed in a 4000- mL container at 1073 K, give the final amounts of the various species. CaCO3 = Caos DOO CO2 = (b) The same as (a), except 0.50 g of CaCO3 is placed in the container. CaCO3 = DO Ca0 = CO2 =
Fill in the Blanks At 1073 K, the equilibrium pressure of carbon dioxide above mixtures of calcium carbonate and calcium oxide is 183 torr. (a) If 5.0 g of solid calcium carbonate is placed in a 4000-ml container at 1073K, give the final amounts of the various species. CaCO3 = Ca0 = CO2 = (b) The same as (a), except 0.50 g of CaCO3 is placed in the container, CaCO3 = Cao CO2- Unanswered