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4. You arrive at a bus stop at 10 oclock, knowing that the bus will arrive at some time uniformly distributed between 10:00

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Answer #1

let time 10:00 is t=0 , and 10:30 =30 minutes

here for uniform distribution parameter a =0 and b=30

a)

probability = P(X>10)= 1-P(X<10)= 1-(10-0)/(30-0)= 2/3 =0.6667

b)

P(wait for more than 12 minutes given waited 10 minutes) =P(X>12|X>!0) =P(X>12)/P(X>10)

=((30-12)/(30-0))/((30-10)/(30-0)) =18/20 =0.9

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