Question

The time a bus will arrive is uniformly distributed from 8:00 AM until 8:20 AM. You arrive at the bus stop at exactly 8:00 AM. What is the probability you will wait 12 minutes or more?

Answer 1

Solution:-

The probability you will wait 12 minutes or more is 0.40.

Let a = 0 at 8:00 AM

b = 20 at 8:20 AM

x = 12

For uniform distribution formula for the probability :-

$P(x,a,b)=\frac{b-x}{b-a}$

$P(x\geq 12)=\frac{20-12}{20-0}$

$P(x\geq 12)= 0.40$