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E A normal population has mean l = 50 and standard deviation 0 = 5. What is the 80th percentile of the population? Use the TI
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DISTE DRAW 1: normalpdf normalcdf 3: invNorma 4: invTC 5:Updf 6: tedfc 7+X2 pdf

Area = 0.80

Mean = 50

Standard deviation = 5

invNorm(0.8, 50,5 54.20810617

80th Percentile is 54.208106

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