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1 2 3 4 5 6 7 Question 6 of 8 (1 point) Attempt 2 of Unlimited 6.2 Section Exercise sample of size 7 will be drawn from a nor
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Answer #1

a)

Yes, normal distribution is appropriate here to find the probabilities of x bar.

b)

o = Z n - X

mean = 63, S.D = 15

When X = 53

z = (53 - 63) / 15 = -10/15 = -0.67

which gives 0.2514 in the z-table.

When X = 73

z = (73 - 63) /15 = 10/15 = 0.67

which gives 0.7486 in the z-table.

Therefore, the area between them will be (0.7486 - 0.2514), which is 0.4972.

P = 0.4972

c)

The 83rd percentile can be calculated using the dataset here.

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