Question

rface. For this situation (see the table below, all distances are in centimeters), n, is the -) on the same side of the surface as object O or on the opposite side. (b) (c) Enne R/V Side 2.7 +140 -39 +460 DBLEM VIDEO MINI-LECTURE oint Potential Policy set by your instructor. Ins

Spherical refracting surfaces. An object O stands on the central axis of a spherical refracting surface. For this situation, the data in the table below refers to the index of refraction n1 where the object is located, the index of refraction n2 on the other side of the refracting surface, the object distance p, the radius of curvature r of the surface, and the image distance i. (All distances are in centimeters.) Fill in the missing information, including whether the image is real or virtual, and on the same side of the surface as object O or on the opposite side. (The N2 needs to be filled in...that is what needs to be solved for, last part already done (real, opposite) )

n1= 2.7 , p= 140 , r= -39 , i= 460

N2 = ? And unit ?

R/v = is it ( real or virtual )

Side = is it ( same or opposite)

Answer 1

Incident Ray mo Refracted Ray. surface. frected say p = pole. Trident Ray. I c= centre of spherical spherical gout Surface O= Object I= Image. Song Sign Convention : 1) Direction of incident Ray is taken as positive opposite to it is negative. 2) All distances are measured from pole P. The situation of the question is shaune bele, above in the ray diagram. Taking paraxial approximation and using refran the formula of refraction from spherical surface which N-ng ro= a= R = Image distance object " Radius of Genta a curvative

man - 2.7 = n2 - to 2.7 460 140 - 39 12 = 301827 M = 3.182 Refactive index is the Patio of speed rattar light in vacuum to the Image is real speed of light in mediuan. . It is dimensionless. The actual rays intersect to form real gmage Side = Image it on the same side as the object! which is virtual I