Suppose you have two RAID arrays, one implementing RAID 3, the other RAID 5. Each has...
Suppose you have two RAID arrays, one implementing RAID 3, the other RAID 5. Each has 9 disk drives in its array. If the RAID 5 array can read a 1 Kbyte of data in 16 ms, how long would you expect the RAID 3 array to take to read 1 Kbyte of data? Why?
Homework Answers
In the system we have two types of RAID (RAID 3 and RAID 5) with 9 disks. At high level following are the key charactestics of these RAID implementations:
RAID 3:
- Stores data in different HDD.
- Parity is stored in one HDD so all data srips in n-1 HDD and one HDD for Parity.
- Byte wise striping
- Party is bitwise.
- Write Performance is poor and read is fair.
RAID 5:
- Stores data in blocks in different HDD and all HDD are used for data.
- Parity is distributed across all HDD.
- Block wise stripping
- Parity is Block wise.
- Read data is very fast however write is slower as needs to calculate parity.
since in RAID 3 data is stripped bytewise and RAID 5 its blockwise (Assume 128 Bytes of block). Assuming all disk controllers are allow parallel access of all 9 disks.
RAID5 access time =16 ms that is accessing all 9 disk and having one read is ataking 16 msec time.
In RAID 3 we have Byte striping so even accessing 128 Bytes on disks we need (128/8=16 read cycle).
Therefore accessing 1 KB of data will take 16 reads in RAID 3 where 1 read is 16 ms
Total access time of RAID 3 for 1 KB of data=16*16=256 ms.
The detailed explanation clearly showing why RAID 3 is taking large time then RAID 5 for same disk configuration and now a days RAID 3 is obsolete.
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