Write a C program that accepts a phone number of the form +1(xxx)-xxx-xxxx
where x is a digit, and displays the sum of all digits in the phone number.
#include<stdio.h>
int main(){
char phone[20] ;
int a;
int total = 0;
printf("Enter the phone number in the form +1(xxx)-xxx-xxxx
\n");
//Getting the phone number and save it in the character array
gets(phone);
//for loop is to iterate over the character array to find the
total
for(a = 2; a <= 20; a++){//initial a= 2 to ignore the '+1'
switch(phone[a]){
case '1':
total = total+1;
break;
case '2':
total = total+2;
break;
case '3':
total = total+3;
break;
case '4':
total = total+4;
break;
case '5':
total = total+5;
break;
case '6':
total = total+6;
break;
case '7':
total = total+7;
break;
case '8':
total = total+8;
break;
case '9':
total = total+9;
break;
default:
total= total+0;
break;
}
}
printf("Total of the digits of the phone number is %d",
total);
return 0;
}
Write a C program that accepts a phone number of the form +1(xxx)-xxx-xxxx where x is...
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