electromechanical engergy conversion
please use the figure below to solve the problem
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electromechanical engergy conversion please use the figure below to solve the problem 1-19. Figure PI-14 shows...
1) Figure- generator is producing a line voltage of 480 V, and the line impedance is 0.09 + j0.16 . Load 1 is Y connected, with a phase impedance of 2.5236.87° 0 and load 2 is A connected, with a phase impedance of 54-20° n. shows a three-phase power system with two loads. The A-connected 2 0.09 j0.16 n w Vca= 4802-240° V + Vab = 48020 V Vhc = 480-120° V 0.09 j0.16 0.09 j0.16 Load 1 Load 2...
solve fast please help me please faaaast Q3: in the following figure find: 1. The power factor seen by the source 2- Apparent power, active power and reactive power for all loads 3- Is 1.5 kW -0.8 KVAR 1 S Load 2 200 290 V 21 5K VA 0.75 PF Leading 8K W 0.85 PF Lagging Load 1 Load 3
2) A 480 V, 60 Hz, 400 hp 0.8 PF-lagging eight-pole A-connected synchronous motor has a synchronous reactance of 0.6 and negligible armature resistance. Ignore the mechanical and core losses. The magnitude of the internal machine voltage is 480 V when the field current is 4 A. Assume magnetic linearity. Initially, the motor operates at the rated conditions. a) Find the speed of this motor. b) Find the armature and field currents. c) What is the developed torque? What is...
10. Two loads connected in parallel draw a total of 2.4 kW at 0.8 pflagging from a 120-V rms, 60- Hz line. One load absorbs 1.5 kW at a 0.707 pf lagging. Determine: (a) the pf of the second load, INV 11. Calculate the line currents for the system shown in figure. Calculate also the total power and reactive power consumed by the load. w 12. For the balanced three-phase circuit in Fig.. Calculate the line currents, the phase voltage...
Please show all work Problem #2 For the three-phase balanced system shown in the figure determine the following: 1. V and I 2. The three-phase power absorbed by the load. 3. The real and reactive three-phase powers lost in the transmission line. Р 4. The power efficiency, N =- -Load *100. of the three-phase system. Source V = 100 20° V. a 112 j122 A + ommo 15+ j2102 D=1002-120V.. 12 122 B 15+j2102 15+ j2 152 D =100420 V...
VO) L1 L2 Line VO LI Power Calculations Learning Goal: In this tutorial, you will practice the calculation of power in circuits containing loads, including the effects of non-ideal transmission lines, and practice how to improve the power factor for an entire system. Many appliances (eg., hair dryers, coffee makers, and refrigerators) and industrial loads are powered by AC sources. The ability to be able to calculate their power needs is important in a number of situations. Before completing this...
Power Calculations 4 of 4 Review Learning Goal In this trial, you will practice the callation of power in circuts cortaring loads, including the effects of non-ideal transmission Ines, and practice how to improve the power factor for an entire system. Many appliancese.. hair dryers, coffee makers, and refrigerators) and indoads are powered by AC sources The folly to be able to calculate the power needs is important ma number of towns. Before completing the Moral make sure you are...
1. In the figure below, what is the correct equation to find the value of capacitor C to be connected in parallel with the source Vg to improve the power factor angle of the circuits from oto 02. (2 Marks) the - 230 v.co 10 a.) c= P(tano, - tano,) c) c= P(tand, -tano,) wV av b.) c="(tano, -tane) d) c= P(tand,+ tano.) 2. The type of power which is actually consumed or utilized in an AC circuit is called:...
solve no: 3.14 , 3.16, 3.19 please show each step and solve for beginners 120 Power System Analysis 3.12. A single-phase system similar to that shown in Figure 3.11 has two transformers A-B a B-C connected by a line B feeding a load at the receiving end C. The ratings and parame ter values of the components are 500 V/1.5 kV, 9.6 kVA. leakage reactance 5 % 1.2 kV/120 V, 7.2 kVA, leakage reactance 4 % series impedance (0.5 +...
The three figures below show a balanced three phase Delta, its Wye equivalent and the single phase equivalent of the three phase Wye. All three representations have a complex load ZALD or ZYLD and a complex line impedance ZLINE Refer to these diagrams when answering questions 1-4. ZLINE Vab= 679 L 30° ZLINE ZALD ZLINE = 2+1 DELTA ZALD= 18+24j2 LINE ZLINE ZLINE ZYLD 7yun WYE WYE ZYLD ZLINE ZLINE Van Complex Load ZYLD Single Line WYE 1) In the...