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VO) L1 L2Line VO LIPower Calculations Learning Goal: In this tutorial, you will practice the calculation of power in circuits containing loads,Part A - Power and power factor for parallel loads Consider the two loads in the circuit in (Figure 1). Load #1 (L1) absorbsPart B - Power for a parallel load with a transmission line impedance Consider the circuit in (Figure 2). The load (L1) absorPart C-Power factor correction Consider the two loads in the circuit in (Figure 1). Load #1 (L1) absorbs S = 56 VA at a laggi

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256 KVA Xox 66 A si S2 = 56RVA 4 56kVA 425LOV @ 0.66 leadpf @ logging pf = 0.66 (60H2) Q =-js, * sin [oo-1 (44)] / since forline I ZL F P256W (0-055+;0-005) 48V2 QaVK TV(A) V SLI (S), 2 56 +1) VA J* = (ta /tan- (t))* I- 7.588 /–1•023 line complessPret: 2 Pi + P2 (Soop) + 56 (56*0.61) + 56 9.16 W 2 to not 2 dit Q2 si sing to 2 56% [sin (1009(0-61)]] +1 44-37+1 And a 45.3

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