Question

PROBLEM DESCRIPTION (see figure 1) INTERVAL 1- A toy car leaves point A and goes to point B at a constant velocity of 21 in/sec, it INTERVAL 2-When it reaches point B, an acceleration is applied a(t) [4.5t3-11t+6t+3] for INTERVAL3- The toy car reaches the top of the ramp and goes flying off the ramp. goes up a ramp of 21 degrees. 0.7 seconds after reaching point B. AFTER THIS TIME a(t) -0 40in. 11 inches ramp to Figure 1 QUESTIONS Points question 10 pts 1. At what time ta does the toy car reach point B from point A? /15 pts 2. Determine the expression for velocity v t)forINTERVL2 15 pts 3. Determine the expression for displacement s(t) for INTERVAL 2 10 pts 4. How far has the toy car traveled 1.5 seconds after passing point B? 10 pts 5. At what velocity does the toy car fly off the ramp? ono / 10 pts 6. At what time tc does the toy car reach point C? 15 pts-. 15 pts How high does the toy cargo respect to point C? How, far does the toy car go respect to point ??

Answer 1

Gigen clarta acceleoatton 8 appñed aftev B por o Ww Calculate the time tA faom a cay seach poine Pora int A tdistance selociy eC integata on both Sicles we ad t 6 E

4- 4- tA sec andio/sec an be sobscttube &1 1.las, 8.)4-3. 66"(%)\ปใǐ):3刽+С, a, , 2. 1 QI 1. 399 117 + CI C I 1-1, 399 117 Wer dis place ment Canbe Caiculate d t Entegoating on both sides uJe 19c 3

e sec8in n be sobsei tute a I 196 QI distance taa velled a Sec a wew alculate the afeer pa ssing point (079sec QI

-(83. 669-8) in 4 (1-08) -83. 4Q66 t 8 sec tyaDe Ited alistan ce dl t 。", Total = 15.664 t )8.79 Toeal. istance toa Selled30 t