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C(6.1)C(4,3) - 6.4 = 24 80 + 90 + 24 194 Total: As you can see, in our solution to Example 10, we needed to calculate only th
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18) It is given that among 18 computers, 12 are in working order and six are defective.

Now we have to find out how many samples of 4 are possible, selected without replacement and without regard to order, wherein all are defective.

Thus, we know that we have to choose only from the defective ones. Thus, we have to choose 4 from the 6 defective.

Thus, the required answer is given by 6C4 = 6! / (4!*2!) = 15

Thus, 15 samples of four are possible selected without replacement and without regard to the order wherein all are defective.

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